Answer:
sorry I tried But Don't Know The Answer
1. The tables represent a ratio of 3:5. For example, 6 x 3 = 18, and 6 x 5 = 30. Also, 20 x 3 = 60, and 20 x 5 = 100.
2. The table has a ratio of 3:4, so the missing blank is 64.
First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
Answer:
A, D, E
Step-by-step explanation:
