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Murrr4er [49]
2 years ago
5

What part of the water cycle involves the leaves of plants

Chemistry
1 answer:
zvonat [6]2 years ago
5 0

Answer: The answer to this question is transpiration.

Explanation: I know this answer because i looked it up in a book. The other explanation is I study about this a lot.

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Both renewable and nonrenewable resources are used with our society. How do the uses of nonrenewable resources compared to the u
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Nonrenewable we only use them and renewable we can use them over and over.
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A mystery element contains 11 electrons. Which group of the periodic table will it belong to?
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There are 18 Elements in the fifth period.
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3 years ago
How many moles are present in 1.75 g of zinc sulfate, Znso, ?
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Explanation:

We assume you are converting between grams ZnSO4 and mole. You can view more details on each measurement unit: molecular weight of ZnSO4 or mol This compound is also known as Zinc Sulfate. The SI base unit for amount of substance is the mole. 1 grams ZnSO4 is equal to 0.0061941519772353 mole.

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3 years ago
Read the two statements given below. Statement 1: All living matter at the smallest level is made of cells Statement 2: New anim
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Answer:

Statement 1: All living matter at the smallest level is made of cells

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Hope this helps

7 0
3 years ago
A rigid tank contains 1.40 moles of an ideal gas. Determine the number of moles of gas that must be withdrawn from the tank to l
sergey [27]

Answer : The final number of moles of gas that withdrawn from the tank to lower the pressure of the gas must be, 0.301 mol.

Explanation :

As we know that:

PV=nRT

At constant volume and temperature of gas, the pressure will be directly proportional to the number of moles of gas.

The relation between  pressure and number of moles of gas will be:

\frac{P_1}{P_2}=\frac{n_1}{n_2}

where,

P_1 = initial pressure of gas = 24.5 atm

P_2 = final pressure of gas = 5.30 atm

n_1 = initial number of moles of gas = 1.40 moles

n_2 = final number of moles of gas = ?

Now put all the given values in the above expression, we get:

\frac{24.5atm}{5.30atm}=\frac{1.40mol}{n_2}

n_2=0.301mol

Therefore, the final number of moles of gas that withdrawn from the tank to lower the pressure of the gas must be, 0.301 mol.

8 0
2 years ago
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