<span>Displacement of the oscillator can be expressed in the mathematical form as:
x(t) = A*cos (ωt + δ),
therefore acceleration would be represented as => a = ¨x = â’ω^2*A*cos (ωt + δ),
the maximum acceleration will happen when the cosine is -1.
Hence, maximum acceleration => a-max = A*ω^2
The force associated with acceleration is F = ma.
Therefore maximum amplitude is
A = F / (m*ω^2)
= F / (4Ď€^2 * m * f^2) where f is the frequency of oscillation.
putting values in above equation we ge:
A = 50000 / 4Ď€^2 * 10^â’4 Ă— (10^6)^2
= 1.25 * 10^â’5
hence 1.25 * 10^-5 m/s^2</span>
Answer:
1200N
Explanation:
Suppose a body of mass "m" and its weight on the moon is Wm (where W is the weight and "m" is the moon ;which means weight on the moon).Mass of the moon is "M"
and its radius is "R"
Weight of an object on the moon = "F"(Force)with which the moon pulls.
Wm = GM*m/r2
Weight of the same object on the earth is We(where W is the weight and "e" is the earth; which means weight on the earth).
Mass of the earth is 100 times of that of the moon.
Radius of the moon = R
Radius of the Earth = 4R
Weight of the object on the moon =
We = G100M*m/(4R)2(Pronounced 4 R square)
We = G100M*m/(16R)2(Pronounced 16 R square)
Wm/We = G * M * m * 16R2/R2 * g * 100M * m
=16/100
Therefore, 4800N on earth= 1200N on moon
Producers generate food for primary consumers. They are the basis of the food web because without them, there would be no food web.
Answer:
You have a displacement of 5 units to the right.
Explanation:
First you go three to the right which lands on the 3 mark. Then you move it 4 to the left which substracts 4, landing the object at -1. Finally you move 6 to the right, and you finish at marker 5. Since displacement is not total distance but just final distance from the start point directly to end point, it is only a displacement of 5.
Answer:
there are 25 kg objective travelling at 2m/s to the right.