Answer:
The acceleration of the snowball is 0.3125
Explanation:
The initial speed of the snowball up the hill, u = 0
The speed the snowball reaches, v = 5 m/s
The length of the hill, s = 40 m
The equation of motion of the snowball given the above parameters is therefore;
v² = u² + 2·a·s
Where;
a = The acceleration of the snowball
Plugging in the values, we have;
5² = 0² + 2 × a × 40
∴ 2 × 40 × a = 5² = 25
80 × a = 25
a = 25/80 = 5/16
a = The acceleration of the snowball = 5/16 m/s².
The acceleration of the snowball = 5/16 m/s² = 0.3125 m/s² .
Answer;
B. The field is most concentrated at the poles of the magnet
Explanation;
A bar magnet is a rectangular object that has a magnetic field. It is usually made of iron or steel, but it can also be made of any ferromagnetic substance or a ferromagnetic composite.
The magnetic field of a bar magnet is strongest at either pole of the magnet. It is equally strong at the north pole compared with the south pole. The force is weaker in the middle of the magnet and halfway between the pole and the center.
If small compasses are used to map the magnetic field around a bar magnet, they will point in the direction away from the north pole of the magnet, toward the south pole of the magnet
Answer:
Current needed = 704A
Explanation:
Using the fomula; torque(τ) = (I)(A)(B)Sinθ
Where B = uniform magnetic field
I = current and A = Area
Diameter = 19cm = 0.19m so, radius = 0.19/2 = 0.095m
Area(A) = πr^(2) = πr^(2)
= π(0.095)^(2) = 0.0284 m^(2)
Now, B(earth)= 5x10^-5 T
While, we can ignore the angle because it's insignificant since the angle of the wire is oriented for maximum torque in the earth's field.
Now, if we arrange the formula to solve for charge (I):
I = (τ)/(A)(B)
I = (1.0x10^-3) / (0.0284)(5x10^-5)
I = 704A
Answer: 62.5 km/hour is the average velocity of the train.
Explanation:
Displacement of the train = 100 km + 150 km = 250 km
Total time train took =1 hour 15 min+ 45 min + 2 hours = 240 min = 4 hours
Average velocity=
62.5 km/hour is the average velocity of the train.
Answer:
Velocity on the right side of the cart 
Explanation:
Given
⇒The mass on the left of the cart 
Its velocity 
,
⇒Mass on the right of the cart 
Velocity
We have to find 
From
The law of conservation of linear momentum:
We can say that.
Initial momentum will equalize the final momentum.
And momentum is the product of mass and its velocity.
Assigning one of its velocity as negative because both are in different direction.
Lets call 
Recalling the formula and plugging the values.
So the velocity of the cart on the right side that has a mass of 
is 
