Answer:
The answer would be A. - the temperature remains constant
Explanation:
An isothermal process is a change of a system, in which the temperature remains constant: ΔT = 0
Answer:
∆T = Mv^2Y/2Cp
Explanation:
Formula for Kinetic energy of the vessel = 1/2mv^2
Increase in internal energy Δu = nCVΔT
where n is the number of moles of the gas in vessel.
When the vessel is to stop suddenly, its kinetic energy will be used to increase the temperature of the gas
We say
1/2mv^2 = ∆u
1/2mv^2 = nCv∆T
Since n = m/M
1/2mv^2 = mCv∆T/M
Making ∆T subject of the formula we have
∆T = Mv^2/2Cv
Multiple the RHS by Cp/Cp
∆T = Mv^2/2Cv *Cp/Cp
Since Y = Cp/CV
∆T = Mv^2Y/2Cp k
Since CV = R/Y - 1
We could also have
∆T = Mv^2(Y - 1)/2R k
Answer:
210 m
Explanation:
Given:
a = -6.8 m/s²
v₀ = 54 m/s
v = 0 m/s
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (54 m/s)² + 2 (-6.8 m/s²) Δx
Δx ≈ 210 m
