I'm pretty sure there is only one element named after Mendeleev: <span>Mendelevium.</span>
Ek = (m*V^2) / 2 where m is mass and V is speed, then we can take this equation and manipulate it a little to isolate the speed.
Ek = mv^2 / 2 — multiply both sides by 2
2Ek = mv^2 — divide both sides by m
2Ek / m = V^2 — switch sides
V^2 = 2Ek / m — plug in values
V^2 = 2*30J / 34kg
V^2 = 60J/34kg
V^2 = 1.76 m/s — sqrt of both sides
V = sqrt(1.76)
V = 1.32m/s (roughly)
<span>D. Atoms of all elements contain protons, but the number of protons is different for every element.
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Answer:
The answer to your question is: V2 = 1 l
Explanation:
Data
P1 = 200 kPa
P2 = 300 kPa
V1 = 1.5 l
V2 = ?
Formula
P1V1 = P2V2
V2 = (P1V1) / P2
V2 = (200 x 1.5) / 300
V2 = 1 l
Answer:
We conclude that the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.
Explanation:
Given
To determine
Kinetic Energy (K.E) = ?
We know that a body can possess energy due to its movement — Kinetic Energy.
Kinetic Energy (K.E) can be determined using the formula

where
- K.E is the Kinetic Energy (J)
now substituting m = 1.75, and v = 54 in the formula



J
Therefore, the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.