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Sav [38]
3 years ago
8

A car is pushed with a force of 450 N for 19.4 seconds. What impulse was applied to the car?​

Physics
1 answer:
harina [27]3 years ago
6 0

Answer:

impulse = 8820 kg·\frac{m}{s} or 8820 N·s

Explanation:

Impulse J is equal to the average force F_{av} multiplied by the elapsed time Δt or in equation form, J = F_{av}Δt

As long as your force of 450 N is constant then that value is your average force F_{av} and your elapsed time is 19.4 seconds.

Multiply these values.

You will get an impulse of 8820 kg·\frac{m}{s} or 8820 N·s.

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