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DiKsa [7]
3 years ago
7

What volume of O2 is required to react with CS2 to produce 4 liters of CO2?

Chemistry
1 answer:
Alenkasestr [34]3 years ago
3 0

Answer:

12 L of O₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CS₂ + 3O₂ —> CO₂ + 2SO₂

From the balanced equation above,

3 L of O₂ reacted to produce 1 L of CO₂.

Finally, we shall determine the volume of O₂ required to produce 4 L of CO₂. This can be obtained as follow:

From the balanced equation above,

3 L of O₂ reacted to produce 1 L of CO₂.

Therefore, xL of O₂ will react to produce 4 L of CO₂ i.e

xL of O₂ = 3 × 4

xL of O₂ = 12 L

Thus, 12 L of O₂ is needed for the reaction.

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Answer:

Check explanation

Explanation:

From the question, the parameters given are 64.7g of benzene,C6H6; a starting temperature of 41.9°C and bringing it to 33.2°C.

Molar mass of benzene,C6H6= 78.11236 g/mol.

Things to know: heat capacity of benzene, C6H6= 1.63 J/g.K, the heat of fusion = 9.87 kj/mol.

STEP ONE(1): ENERGY USED IN MELTING BENZENE SOLID.

Using the formula below;

Energy used in melting the solid(in JOULES) = (mass of benzene/molar mass of benzene) × heat of Fusion.

=(64.7 g of C6H6/ 78.11236(g per mol) of C6H6) × 9.87 kJ per mol.

= 8.175 J.

= 0.008175 kJ.

STEP TWO (2): ENERGY OF HEATING THE LIQUID.

It can be calculated from the formula below;

Energy= heat capacity (J/g.K) × mass of benzene× (∆T).

= 1.63 J/g.K × 64.7 × (41.9-33.2).

= 917.5J.

= 0.9175 kJ.

Energy required to boil benzene= Energy required to melt the bezene + energy required for boiling.

= 0.008175+ 0.9175.

= 0.93kJ

Approximately, 1 kJ

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