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ivann1987 [24]
3 years ago
9

Grams of sodium 9.5g in NaCl ​

Chemistry
1 answer:
Kitty [74]3 years ago
4 0

Answer:

3.68 grams.

Explanation:

First we <u>convert 9.5 g of NaCl into moles of NaCl</u>, using its<em> molar mass</em>:

9.5 g ÷ 58.44 g/mol = 0.16 mol NaCl

In<em> 0.16 moles of NaCl there are 0.16 moles of sodium </em>as well.

We now <u>convert 0.16 moles of sodium into grams</u>, using <em>sodium's molar mass</em>:

0.16 mol * 23 g/mol = 3.68 g

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3 years ago
a titration of 25.0mL of an x M hcl solution with 0.15M NaOH starts at a burette reading for NaOH of 0.20mL . Thr burette readin
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The kb of hypochlorous acid is 3. 0×10^–8 at 26. 0 C. What is the percent of ionization of hypochlorous?
astraxan [27]

The acid dissociation constant (Ka) defines the difference between a weak and a strong acid. The % ionization of hypochlorous acid is 0.14%.

<h3>What is the acid dissociation constant?</h3>

The acid dissociation constant is used to define the ionization constant of an acidic substance. It gives the quantitative measurement of the strength.

The ICE table is attached to the image below.

The acid dissociation constant (Ka) for the reaction is,

Ka = [H⁺][ClO⁻] ÷ [HClO]

= a² ÷ (0.015 - a)

= 3.0 x 10⁻⁸

Now, a² + 3.0 x 10⁻⁸ a - 4.5 × 10⁻¹⁰ = 0

So, a = 2.210 × 10⁻⁵

Solving further,

[H+] = a = 2.210 × 10⁻⁵ M

The percent ionization is calculated as,

[H+] ÷ [HClO] × 100

= 2.210 × 10⁻⁵ M ÷ 0.015 × 100

= 0.14 %

Therefore, 0.14 % is the percentage of hypochlorous ionization.

Learn more about acid dissociation constant here:

brainly.com/question/22668939

#SPJ4

Your question is incomplete, but most probably your full question was, The ka of hypochlorous acid (HClO) is 3.0 x 10⁻⁸ at 25.0°C. What is the % of ionization of hypochlorous acid in a 0.015 aqueous solution of HClO at 25.0C?

6 0
1 year ago
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