Write a balanced half-reaction for the reduction of permanganate ion mno−4 to solid manganese dioxide mno2 in acidic aqueous sol
1 answer:
The half-reaction includes either the reduction or the oxidation reaction of the redox reactions. In acidic solution permanganate ion will react with hydrogen ion to yield manganese ion and water.
<h3>What are Redox reactions?</h3>
Redox or oxidation-reduction reactions are the chemical reactions in which the oxidation and the reduction of the chemical species occur simultaneously.
Permanganate (VII) ion is a strong oxidizing agent and gets easily reduced to manganese ion in presence of the hydrogen ion in an acidic solution.
The balanced half-reaction for reduction is shown as,
Learn more about reduction reactions here:
#SPJ4
You might be interested in
Answer : The pH of the solution is, 5.24
Explanation :
First we have to calculate the volume of
Formula used :
where,
are the initial molarity and volume of
.
are the final molarity and volume of
.
We are given:
Putting values in above equation, we get:
Now we have to calculate the total volume of solution.
Total volume of solution = Volume of + Volume of
Total volume of solution = 160.0 mL + 1086.79 mL
Total volume of solution = 1246.79 mL
Now we have to calculate the Concentration of salt.
Now we have to calculate the pH of the solution.
At equivalence point,
Thus, the pH of the solution is, 5.24