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scoray [572]
2 years ago
15

Write a balanced half-reaction for the reduction of permanganate ion mno−4 to solid manganese dioxide mno2 in acidic aqueous sol

ution. Be sure to add physical state symbols where appropriate
Chemistry
1 answer:
Svetlanka [38]2 years ago
8 0

The half-reaction includes either the reduction or the oxidation reaction of the redox reactions. In acidic solution permanganate ion will react with hydrogen ion to yield manganese ion and water.

<h3>What are Redox reactions?</h3>

Redox or oxidation-reduction reactions are the chemical reactions in which the oxidation and the reduction of the chemical species occur simultaneously.

Permanganate (VII) ion is a strong oxidizing agent and gets easily reduced to manganese ion in presence of the hydrogen ion in an acidic solution.

The balanced half-reaction for reduction is shown as,

\rm MnO_{4}^{-} \; (aq)+ 8H^{+} \; (aq)+ 5e^{-} \rightarrow Mn^{2+} \; (aq)+ 4H_{2}O \; (l)

Learn more about reduction reactions here:

brainly.com/question/10084275

#SPJ4

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Exposing a 250 mL sample of water at 20.∘C to an atmosphere containing a gaseous solute at 27.59 kPa resulted in the dissolution
ElenaW [278]

Answer : The solubility of this gaseous solute will be, 5.18\times 10^{-5}g/mL

Explanation :

First we have to calculate the concentration of solute.

\text{Concentration of solute}=\frac{Mass}{Volume}=\frac{4.51\times 10^{-3}g}{250mL}=1.80\times 10^{-5}g/mL

Now we have to calculate the Henry's law constant.

Using Henry's law :

C=k_H\times p

where,

C = concentration of solute = 1.80\times 10^{-5}g/mL

p = partial pressure = 27.59 kPa

k_H = Henry's law constant = ?

Now put all the given values in the above formula, we get:

1.80\times 10^{-5}g/mL=k_H\times (27.59kPa)

K_H=6.52\times 10^{-7}g/mL.kPa

Now we have to calculate the solubility of this gaseous solute when its pressure is 79.39 kPa.

C_{(79.39kPa)}=k_H\times p

C_{(79.39kPa)}=(6.52\times 10^{-7}g/mL.kPa)\times (79.39kPa)

C_{(79.39kPa)}=5.18\times 10^{-5}g/mL

Therefore, the solubility of this gaseous solute will be, 5.18\times 10^{-5}g/mL

7 0
3 years ago
How do you know that some substances in coffee beans are soluble?
Fantom [35]

Answer:

When you make coffee, some of the compounds from the ground coffee end up in the water, giving it the distinctive color, aroma, and flavor that we associate with coffee. The solubility of some coffee constituents varies depending on the temperature of the water.

Explanation:

8 0
2 years ago
How do scientists measure the idea of time so long ago?
professor190 [17]

The Ancient Egyptians used simple sundials and divided days into smaller parts, and it has been suggested that as early as 1,500BC, they divided the interval between sunrise and sunset into 12 parts. ... Known as a clepsydra, it uses a flow of water to measure time.

6 0
2 years ago
What is the empirical formula of a compound that is composed of 60.94% carbon 15.36% hydrogen and 23.70% nitrogen
Musya8 [376]

Answer:

C₃H₉N

Explanation:

The empirical formula of a compound is the fundamental and basic possible formula that shows the mole ratio of the atoms of each element in a molecule of the compound.

mole ratio of carbon = 60.94/12 = 5.078

mole ratio of hydrogen = 15.36/1  = 15.36

mole ratio of nitrogen = 23.70/14 = 1.693

Now; we will divide by the smallest value

So; carbon = 5.078/1.693 = 2.99 ≅ 3.0

hydrogen = 15.36/1.693 = 9.07 ≅ 9.0

nitrogen = 1.693/1.693 = 1 ≅ 1

Thus,  the empirical formula is = C₃H₉N

6 0
3 years ago
On a flight to Europe, you notice that the packages of peanuts are puffed up. Why? 1. The jet is over-pressurized at high altitu
hodyreva [135]

Answer:

The correct answer is;

5. They were packaged at a higher pressure on the ground, thus causing the gas inside the packages to expand in the sky where the jet is at a lower pressure.

Explanation:

According to Boyle's law, the pressure of a given mass of gas is inversely proportional to it volume at constant temperature

P₁·V₁ = P₂·V₂

At the factories, the peanuts are packaged at atmospheric conditions whereby P₁ = 1 atm, however, the pressure of the air in the atmosphere decreases with altitude as such the pressure in the airplane jet is about a fraction of hat on the ground by about a factor of 0.7.

Therefore P₂ = 0.7 atm and we have

V₂ = P₁·V₁/P₂ = 1 atm×V₁/0.7 atm = 1.43·V₁

The volume increases at high altitudes

7 0
3 years ago
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