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scoray [572]
2 years ago
15

Write a balanced half-reaction for the reduction of permanganate ion mno−4 to solid manganese dioxide mno2 in acidic aqueous sol

ution. Be sure to add physical state symbols where appropriate
Chemistry
1 answer:
Svetlanka [38]2 years ago
8 0

The half-reaction includes either the reduction or the oxidation reaction of the redox reactions. In acidic solution permanganate ion will react with hydrogen ion to yield manganese ion and water.

<h3>What are Redox reactions?</h3>

Redox or oxidation-reduction reactions are the chemical reactions in which the oxidation and the reduction of the chemical species occur simultaneously.

Permanganate (VII) ion is a strong oxidizing agent and gets easily reduced to manganese ion in presence of the hydrogen ion in an acidic solution.

The balanced half-reaction for reduction is shown as,

\rm MnO_{4}^{-} \; (aq)+ 8H^{+} \; (aq)+ 5e^{-} \rightarrow Mn^{2+} \; (aq)+ 4H_{2}O \; (l)

Learn more about reduction reactions here:

brainly.com/question/10084275

#SPJ4

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The time it takes for a celestial body to make one complete turn on its axis is a(n)
frozen [14]

Answer:

About 24 hours

Explanation:

Think of it as Earths spin

4 0
3 years ago
PLEASE SOMEONE HELP ME WITH THIS
Likurg_2 [28]

Answer:

1.30 moles

Explanation:

As written, the molar mass of the fat is 770.5 g/mole.  Add all the C, H, and O's (I get C48H98O6) and multiply by the molar mass of each.  I obtain the 770.5 grams/mole figure, but would note that a more common fat is actually C3H5(O<u>H</u>(CH2)14(CH3))3 and not C3H5(O<u>O</u>(CH2)14(CH3))3.

Assuming C3H5(OO(CH2)14(CH3))3 is the correct structure, 1000g would mean 1000g/(770.5 g/mole) = 1.298 moles, or 1.30 moles to 2 sig figs.

3 0
3 years ago
How many isomers with a molecular formula of c6h10 contain an internal alkyne?
larisa [96]
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8 0
3 years ago
¿por qué entre el calcio (Ca) que pertenece al segundo grupo y el galio (Ga) que pertenece al tercer grupo hay 10 elementos, ¿Qu
34kurt

Answer:

Estos elementos se denominan metales de transición, metales pesados, elementos del bloque D, etc.

Explanation:

Aquí, en esta pregunta, queremos saber la razón por la cual hay un espacio de 10 elementos entre el calcio, que es un elemento del grupo dos, y el galio, que es un elemento del grupo 3.

Al observar la tabla periódica, la tabla periódica moderna, notamos un bloque de elementos entre los elementos del grupo 2 y los elementos del grupo 3 en la tabla periódica.

Entonces, ¿por qué se colocan estos elementos entre ambos grupos? Se colocan aquí porque no pertenecen en su totalidad al grupo 2, ni tampoco al grupo 3.

Estos elementos presentan una especie de estados de oxidación variables que son responsables de una amplia variedad de propiedades comunes entre ellos.

8 0
3 years ago
Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241
Mazyrski [523]

Answer:

-767,2kJ

Explanation:

It is possible to sum enthalpies of half-reactions to obtain the enthalpy of a global reaction using Hess's law. For the reactions:

1) H₂(g) + ¹/₂O₂(g) ⟶ H₂O(g) ΔH₁= −241.8 kJ

2) X(s) + 2Cl₂(g) ⟶ XCl₄(s) ΔH₂= +361.7 kJ

3) ¹/₂H₂(g) + ¹/₂Cl₂(g) ⟶ HCl (g) ΔH₃= −92.3 kJ

4) X(s) + O₂(g) ⟶ XO₂(s) ΔH₄= − 607.9 kJ

5) H₂O(g) ⟶ H₂O(l) ΔH₅= − 44.0 kJ

The sum of (4) - (2) produce:

6) XCl₄(s) + O₂(g) ⟶ XO₂(s) + 2Cl₂(g) ΔH₆ = ΔH₄ - ΔH₂ = -969,6 kJ

(6) + 4×(3):

7) XCl₄(s) + 2H₂(g) + O₂(g) ⟶ XO₂(s) + 4HCl(g) ΔH₇ = ΔH₆ + 4ΔH₃= -1338,8 kJ

(7) - 2×(1):

8) XCl₄(s) + 2H₂O(g) ⟶ XO₂(s) + 4HCl(g) ΔH₈ = ΔH₇ - 2ΔH₁= -855,2kJ

(8) - 2×(5):

9) XCl₄(s) + 2H₂O(l) ⟶ XO₂(s) + 4HCl(g) ΔH₉ = ΔH₈ - 2ΔH₅= <em>-767,2kJ</em>

I hope it helps!

6 0
3 years ago
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