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daser333 [38]
3 years ago
15

If a flask containing one liter of water was poured into 1,000 small cubes, then each cube would contain:

Chemistry
2 answers:
erastova [34]3 years ago
7 0
Every cube would contain 1 milliliter of water, or .01 liter
anzhelika [568]3 years ago
4 0

Answer is: 1 mL or 1 cm³.

V(water) = 1 L; volume of the water.

One liter is equal to 1000 milliliters (mL) or 1000 cubic centimetres (1000 cm³).

V(water) = 1 L · 1000 mL/L.

V(water) = 1000 mL.

V(cube) = 1000 mL ÷ 1000.

V(cube) = 1 mL; volume of the cube.

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Boyle's law 

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If the particles of matter that make up a substance are relatively far apart and can move freely, the substance is in what state
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Answer:

Gaseous

Explanation:

Gasses can move freely and do not form the shape of their containers

Liquids are more free than solids, but they conform to the shape of their container

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"The molecular formula for hydrogen sulfide is H2S. What does the formula indicate about the composition of a 1.0-gram sample of
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7 0
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Read 2 more answers
Which of the following compounds is SOLUBLE? <br> A. SrSO4 <br> B. CaCO3 <br> C. BaS <br> D. CaCl2
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3 0
3 years ago
15A.4(a) What is the temperature of a two-level system of energy separation equivalent to 400 cm−1 when the population of the up
maksim [4K]

Answer:

T = 525K    

Explanation:

The temperature of the two-level system can be calculated using the equation of Boltzmann distribution:

\frac{N_{i}}{N} = e^{-\Delta E/kT}  (1)

<em>where Ni: is the number of particles in the state i, N: is the total number of particles, ΔE: is the energy separation between the two levels, k: is the Boltzmann constant, and T: is the temperature of the system </em>         

The energy between the two levels (ΔE) is:

\Delta E = hck    

<em>where h: is the Planck constant, c: is the speed of light and k: is the wavenumber</em>      

\Delta E = 6.63\cdot 10^{-34} J.s \cdot 3\cdot 10^{8}m/s \cdot 4 \cdot 10^{4}m^{-1} = 7.96 \cdot 10^{-21}J  

Solving the equation (1) for T:

T = \frac{-\Delta E}{k \cdot Ln(N_{i}/N)}  

<em>With Ni = N/3 and k = 1.38x10⁻²³ J/K, </em><em>the temperature of the two-level system is:</em><em> </em>

T = \frac{-7.96 \cdot 10^{-21}J}{1.38 \cdot 10^{-23} J/K \cdot Ln(N/3N)} = 525K                                  

I hope it helps you!

3 0
3 years ago
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