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Firdavs [7]
3 years ago
5

How much sodium chloride (NaCl) would need to be added to 750 milliliters of water to make a 15% solution?

Chemistry
1 answer:
oee [108]3 years ago
5 0

Answer: 6.58g

Explanation: We are to find the mass of NaCl that can produce 15% solution in a 750ml

STEP 1:

the reaction moles

NaCl + H2O = NaOH + HCl

Therefore 1mole of NaCl reacts with 1mole of H2O

STEP 2:

convert 750ml to liter

750ml × 1L/1000ml = 0.750L

STEP3 :

convert percentage concentration to mol/L

15% = 0.15mol/L

STEP 4:

find the mole

Mole= concentration× volume

0.15mol/L × 0.75L =0.1125mol

STEP 5 :

Find the mass

Mass = mole × molar mass

The molecular mass of NaCl is 23+35.5= 58.5g/mol

Therefore:

0.1125mol × 58.5g/mol = 6.58g

Approximately: 6.6g

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35.4451011

Explanation:

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This equation is not balanced. Click on the coefficient we should change first.<br> help ASAP
horrorfan [7]

Answer:  The coefficient we should change first is for NO_{3}.

Explanation:

The given reaction equation is as follows.

Al + Ni(NO_{3})_{2} \rightarrow Al(NO_{3})_{3} + Ni

Here, number of atoms present on reactant side are as follows.

  • Al = 1
  • Ni = 1
  • NO_{3} = 2

Number of atoms present on the product side are as follows.

  • Al = 1
  • Ni = 1
  • NO_{3} = 3

To balance this equation, multiply Al by 2 and NO_{3} by 3 on reactant side. Also, multiply Al(NO_{3})_{3} by 2 and Ni by 3 on the product side.

Hence, the equation can be rewritten as follows.

2Al + 3Ni(NO_{3})_{2} \rightarrow 2Al(NO_{3})_{3} + 3Ni

Now, number of atoms present on reactant side are as follows.

  • Al = 2
  • Ni = 3
  • NO_{3} = 6

Number of atoms present on product side are as follows.

  • Al = 2
  • Ni = 3
  • NO_{3} = 6

Since, the atoms on both reactant and product side are same. Hence, it is now a balanced chemical equation.

Thus, we can conclude that the coefficient we should change first is for NO_{3}.

7 0
3 years ago
Read the chemical equation.
love history [14]

Answer:

A 2.8 liters

Explanation:

Step 1: Write the balanced equation

N₂ + 3 H₂ ⇄ 2 NH₃

Step 2: Establish the appropriate volume ratio

At the same temperature and pressure, the volume ratio of H₂ to NH₃ is 3:2.

Step 3: Calculate the volume of ammonia produced from 4.2 L of hydrogen

4.2 L H₂ × 2 L NH₃/3 L H₂ = 2.8 L

5 0
3 years ago
ILL GIVE A BRAINLY PLS HELP
Oksana_A [137]

Atoms are the unit of the molecule of the compound. The 3.01 x 10²⁴  atoms of oxygen are present in 5 moles of water and 3 moles of carbon dioxide in the sample.

<h3>What are atoms?</h3>

Atoms are the smallest fundamental unit of the compounds that can be given by Avogadro's number.

For calculating the oxygen atoms in 5 mole water:

If 1 mole = 6.02 × 10²³

Then, 5 moles = 5 ×  6.02 × 10²³

Hence, 3.01 x 10²⁴ atoms of oxygen are present in 5 moles of water.

Moles of carbon dioxide in the sample is calculated as:

If 1 mole of carbon dioxide = 6.02 × 10²³ molecules

Then moles in 1.8 x 10²⁴ molecules will be,

(1.8 x 10²⁴ molecules) ÷ (6.02 × 10²³ molecules)  = 3 moles

Hence, 3 moles of carbon dioxide is present in the sample.

Learn more about Avogadro's number here:

brainly.com/question/5098076

#SPJ1

3 0
2 years ago
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