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Firdavs [7]
3 years ago
5

How much sodium chloride (NaCl) would need to be added to 750 milliliters of water to make a 15% solution?

Chemistry
1 answer:
oee [108]3 years ago
5 0

Answer: 6.58g

Explanation: We are to find the mass of NaCl that can produce 15% solution in a 750ml

STEP 1:

the reaction moles

NaCl + H2O = NaOH + HCl

Therefore 1mole of NaCl reacts with 1mole of H2O

STEP 2:

convert 750ml to liter

750ml × 1L/1000ml = 0.750L

STEP3 :

convert percentage concentration to mol/L

15% = 0.15mol/L

STEP 4:

find the mole

Mole= concentration× volume

0.15mol/L × 0.75L =0.1125mol

STEP 5 :

Find the mass

Mass = mole × molar mass

The molecular mass of NaCl is 23+35.5= 58.5g/mol

Therefore:

0.1125mol × 58.5g/mol = 6.58g

Approximately: 6.6g

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he required empirical formula based on the data provided is Na2CO3.H2O.

<h3>What is empirical formula?</h3>

The term empirical formula refers to the formula of a compound which shows the ratio of each specie present.

We have the following;

Mass of sodium = 37.07-g

Mass of carbonate = 48.39 g

Mass of water = 14.54-g

Number of moles of sodium = 37.07-g/23 g/mol = 2 moles

Number of moles of carbonate = 48.39 g/61 g/mol = 1 mole

Number of moles of water = 14.54/18 g/mol = 1 mole

The mole ratio is 2 : 1: 1

Hence, the required empirical formula is Na2CO3.H2O

Learn more about empirical formula : brainly.com/question/11588623

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