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inysia [295]
3 years ago
10

A 5.00 gram sample of magnesium sulfate hydrate (epsom salt) is heated in the lab to form anhydrous magnesium sulfate. After hea

ting the substance, it is recorded that 2.86 grams of anhydrous magnesium sulfate remain. What is the chemical formula for this sample of magnesium sulfate hydrate
Chemistry
1 answer:
Ostrovityanka [42]3 years ago
5 0

Answer:

The answer to your question is  MgSO₄ 5H₂O

Explanation:

Data

mass of MgSO₄ = 2.86 g

mass of H₂O = 2.14 g (5 - 2.86)

Process

1.- Calculate the molecular mass of the compounds

MgSO₄ = 24 + 32 + (16 x 4) = 120

H₂O = 16 + 2 = 18

2.- Convert the grams obtain to moles

                        120 g of MgSO₄  --------------- 1 mol

                         2.8 g                  ----------------  x

                         x = (2.8 x 1)/120

                        x = 0.024 moles

                         18 g of H₂O --------------------- 1 mol

                         2.14 g           -------------------- x

                         x = (2.14 x 1)/18

                         x = 0.119

3.- Divide by the lowest number of moles

MgSO₄  = 0.024/0.024 = 1

H₂O = 0.119/ 0.024 = 5

4.- Write the molecular formula

                   MgSO₄5H₂O                        

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Answer:

initial temperature=-3.31^{\circ}C

Explanation:

Assuming that the given follows the ideal gas nature;

P_1=0.723atm

V_1=13.5L

T_1=?

P_2=0.612atm

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6Ce^{4+} + I^- + 6OH^- → 6Ce^{3+} + IO_3^- + 3H_2O is the balanced chemical equation.

<h3>What is a balanced chemical equation?</h3>

A balanced chemical reaction is an equation that has equal numbers of each type of atom on both sides of the arrow.

Half-reaction method:

Unbalanced chemical equation:

Ce^{4+} + I^-→ Ce^{3+} + IO^{3-}

Oxidation half-reaction:

I^-+ 6OH^- - 6e- → IO^{3-} + 3H_2O

Reduction half-reaction:

Ce4^+ + e^- → Ce^{3+}

Balanced chemical equation:

6Ce^{4+} + I^- + 6OH^-→ 6Ce^{3+} + IO^{3-} + 3H_2O

Oxidation number method:

Unbalanced chemical equation:

Ce^{4+} + I^-→ Ce^{3+} + IO^{3-}

I^{-1} -6e^-→ I^{+5}

Ce^{4+} + e^- → Ce^{3+}

Balanced chemical equation:

6Ce^{4+} + I^{-1} → 6Ce^{3+} + I^{+5}

or

6Ce^{4+} + I^- + 6OH^-→ 6Ce^{3+} + IO_3^- + 3H_2O

Hence, 6Ce^{4+} + I^- + 6OH^-→ 6Ce^{3+} + IO_3^- + 3H_2O is the balanced chemical equation.

Learn more about the balanced chemical equation here:

https://brainly.in/question/46754758

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