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stepan [7]
3 years ago
5

.......................

Mathematics
1 answer:
padilas [110]3 years ago
8 0

Answer:

its choice 1 can i get brainly

Step-by-step explanation:

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1. a. A cube’s volume is 512 cubic units. What is the length of its edge?
Vanyuwa [196]

Answer:

a) The length of its edge is 8 units.

b) The volume of the sphere is approximately 268.083 cubic units.

c) The fraction of the cube that is taken up by the sphere is 0.524, whose equivalent in percentage form is 52.4 %.

Step-by-step explanation:

a) The volume of a cube (V_{c}), measured in cubic units, is defined by the following expression:

V_{c} = L^{3} (1)

Where L is the side length of the cube, measured in units.

If we know that V_{c} = 512\,u^{3}, then the length of its edge is:

L = \sqrt[3]{V_{c}}

L = 8\,u

The length of its edge is 8 units.

b) The volume of a sphere (V_{s}), measured in cubic units, that fits snugly inside this cube is defined by:

V_{s} = \frac{\pi}{6}\cdot L^{3} (2)

If we know that L = 8\,u, then the volume of the sphere is:

V_{s} \approx 268.083\,u^{3}

The volume of the sphere is approximately 268.083 cubic units.

c) The fraction of the cube taken by the sphere is the ratio of the volume of the sphere to the volume of the cube. That is to say:

r = \frac{V_{s}}{V_{c}}

If we know that V_{c} = 512\,u^{3} and V_{s} \approx 268.083\,u^{3}, then the fraction of the cube that is taken up by the sphere is:

r = 0.524

The result in percentage form is calculated by multiplying the result above by 100.

\% r = 52.4\,\%

The fraction of the cube that is taken up by the sphere is 0.524, whose equivalent in percentage form is 52.4 %.

6 0
3 years ago
A 41 gram sample of a substance that's used to detect explosives has a k-value of 0.1392. Find the substance's half life, in day
-BARSIC- [3]

Answer:

The substance half-life is of 4.98 days.

Step-by-step explanation:

Equation for an amount of a decaying substance:

The equation for the amount of a substance that decay exponentially has the following format:

A(t) = A(0)e^{-kt}

In which k is the decay rate, as a decimal.

k-value of 0.1392.

This means that:

A(t) = A(0)e^{-0.1392t}

Find the substance's half life, in days.

This is t for which A(t) = 0.5A(0). So

A(t) = A(0)e^{-0.1392t}

0.5A(0) = A(0)e^{-0.1392t}

e^{-0.1392t} = 0.5

\ln{e^{-0.1392t}} = \ln{0.5}

-0.1392t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.1392}

t = 4.98

The substance half-life is of 4.98 days.

5 0
3 years ago
There are 90 girls and 60 boys in sixth grade at a middle school. Of these students, 9 girls and 3 boys write left-handed.What p
storchak [24]

Answer:

8%

Step-by-step explanation:

5 0
3 years ago
Chase wanted to graph the point (–4, 3) on the coordinate plane. He drew the point shown.
mestny [16]

Answer:

A

Step-by-step explanation:

you always do the first coordinate then you do the next ones. Alwasy move to the left when doing negatives

8 0
3 years ago
Read 2 more answers
3/12 = y/8 solve for y
PIT_PIT [208]
2 is the answer for y
6 0
4 years ago
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