The particle will have an energy of 12U0. A particle travels at an initial velocity from point B to point A, gaining U0 joules of kinetic energy along the way. The constant force at this point is equal to 12F.
<h3>Does 9.8 represent gravity?</h3>
The acceleration which gravity gives to objects falling freely serves as a gauge of its strength. The gravity's acceleration at Earth's surface is approximately 9.8 meters (32 feet) per second every second.
<h3>What is a good illustration of gravity?</h3>
The following are a few instances of the power of gravity: the energy holding the gases inside the sun. the power behind a ball's descent after being thrown into the air. the force that makes an automobile coast down even when the gas is not depressed.
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Balanced forces<span> act on the same object and </span>Action-Reaction forces<span> act on different objects.</span>
Answer:
block 2 or 4
because of the distribution of weight and force being applied to the object
Answer:
a) 35.75 ft/s
b) 45 ft
Explanation:
<u>Given </u>
Weight W = 100 lbf
mass(m) = 100*32.174/32.2=99.92 lb
decrease in kinetic energy ΔKE = -500 ft.lbf
increase in kinetic energy ΔPE= 1500 ft.lbf
initial velocity V_1 = 40 ft/s
initial height h_1 = 30 ft/s
The gravitational acceleration g = 32.2 ft/s2 Required
(a) Final velocity V_2 (a) Final elevation h_2
<u>Solution </u>
Change in kinetic energy is defined by
ΔKE = .5*m *( V_2 ^2-V_1^2)
Change in potential energy is defined by
ΔKE = W *( h_2 -h_1 )
Then,
-500=.5*99.92*1/32.174*(V_2 ^2-40^2)
V_2=35.75 ft/s
1500 = 100 x (h_2 — 30)
h_2= 45 ft
