a) time, t = 11.407 s, b) distance x = 175.66 m, v = c) speed v = 30.80 m / s
<h3>Explanation of question:</h3>
a) This is kinematics exercise, write the equation of each vehicle car is;-
x = x₀ + v₀ t + ½ a t²
Let's fix our the reference system at a point where the car indicate that the car stops from rest is vo = 0.
x₀ = v₀ = 0
<h3>we substitute</h3>
x = ½ a t²
truck
x₂= v₀ t
v₀ = 15.4 m / s
At the point where they are, positions are equal:-
½ a t² = vo t
t = 2 vo / a
calculate us
t = 2 15.4 / 2.
t = 11.407 s
b) the distance to reach it
x = ½ to t²
x = ½ 20 11.407²
x = 175.66 m
c) the speed of the car is
v = vo + a t
vo = 0
v = at
v = 2.0 11.407
v = 30.80 m / s
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Answer:
no mam
Explanation:
the answer to the question is
Answer:
2.49 seconds
Explanation:
From the question,
a = (v-u)/t............................ Equation 1
Where a = acceleration, v = final velocity, u = initial velocity, t = time
Make t the subject of the equation
t = (v-u)/a.......................... Equation 2
Given: v = 6.5 m/s, u = 11 m/s, a = -1.81 m/s²
Substitute these values into equation 2
t = (6.5-11)/(-1.81)
t = -4.5/-1.81
t = 2.49 s
Parallel has more than one circuit or form of energy
series has only one form of energy circuit
