Answer:
B. 2
Explanation:
The reaction expression is given as:
_S + 3O₂ → 2SO₃
Now let us balanced the expression;
On the product side we have 2 moles of S
On the reactant side we should have 2moles of S
So, we put the coefficient 2 to balance the expression;
We have 6 moles oxygen on both sides
The formula for acceleration is the velocity times the inverse of time so it would be 21 times 1/13. So roughly 0.0769... is the acceleration(m/s^2).
Answer:
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The final velocity is 5.87 m/s
<u>Explanation:</u>
Given-
mass, 
= 72 kg
speed, 
= 5.8 m/s
,
= 45 kg
,
= 12 m/s
Θ = 60°
Final velocity, v = ?
Applying the conservation of momentum:
X + X = ( + ) v
72 X 5.8 + 45 X 12 X cos 60° = (72 + 45) v
v = 417.6 + 540 X 
v = 417.6 + 
v = 5.87 m/s
The final velocity is 5.87 m/s
