All categories

3 years ago

Explain how the sun's position in the sky affects the length of shadows

1 answer:

8 0

A shadow forms on the side of an object that faces away from the sun. The length of shadows changes as Earth rotates. In the morning, the sun is low in the eastern sky and shadows are long. As time passes in the morning, the sun seems to move higher in the sky.

You might be interested in

What speed would a fly with the mass of 0.55 g need in order to have the same kinetic energy as the automobile in the term 19

larisa86 [58]

The question does not provide enough information to complete the answer, so I'll assume the needed data to help you to solve your own problem

Answer:

The fly should need to move at 9,534.6 m/s to have the same kinetic energy as the automobile

Explanation:

Kinetic Energy

Is the capacity of a body to do work due to its speed and is computed by

$\displaystyle K=\frac{mv^2}{2}$

We are not given enough data to compare the kinetic energy of the fly with that of the automobile. We'll assume the following characteristics:

$m_a=500\ kg$

$v_a=10\ m/s$

So its kinetic energy is

$\displaystyle K_a=\frac{(500)10^2}{2}$

$\displaystyle K_a=25,000\ J$

The mass of the fly is

$m_f=0.55\ gr=0.00055\ kg$

To have the same kinetic as the automobile:

$\displaystyle \frac{m_fv_f^2}{2}=25,000$

Solving for $v_f$

$\displaystyle v_f=\sqrt{\frac{2(25,000))}{m_f}}$

$\displaystyle v_f=\sqrt{\frac{50,000}{0.00055}}$

$v_f=9,534.6\ m/s$

The fly should need to move at 9,534.6 m/s to have the same kinetic energy as the automobile

5 0

3 years ago

Ondrea could drive a Jetson's flying car at a constant speed of 540.0 km/hr across oceans and space, approximately how long woul

Tcecarenko [31]

Answer:

The time taken in years is $x = 125 \ years$

Explanation:

From the question we are told that

The speed is $v = 540.00 \ km /hr = \frac{540 *1000}{3600} = 150\ m/s$

The distance from the sun to Pluto is $d = 5.9*10^{9} \ k m = 5.9*10^9 * 1000 = 5.9*10^{12} \ m$

Generally the time taken is mathematically represented as

$t = \frac{d}{v}$

=> $t = \frac{5.9*10^{11}}{150}$

=> $t = 3.933*10^{9}$

Converting to years

$1 year \to 3.154*10^7 \ s$

$x \ years \to 3.933*10^{9}$

=> $x = \frac{ 3.933*10^{9} * 1 }{ 3.154 *10^7}$

=> $x = 125 \ years$

7 0

3 years ago

How can you make the moon go around in a bigger circle

zlopas [31]

You would have to give it more mechanical energy.

Like, strap a bunch of powerful rockets to one side of the moon, with all of them pointing in the direction that the moon is already moving in its orbit. Then blast away.

NOTE: There aren't enough rockets or rocket fuel on Earth to make a difference, even if you used ALL of them. The mass of the moon is about

73,476,730,900,000,000,000,000 kilograms

(rounded to the nearest hundred trillion kilograms.)

That's a lot.

5 0

3 years ago

Read 2 more answers

What is the mass of a 7.0 kilogram bowling ball on the surface of the moon?

babunello [35]

Answer:

1.16kg is the answer. Hope this helped

Explanation:

4 0

2 years ago

The transmission of heat requiring the movement of a liquid or a gas is

AysviL [449]

Answer:

convection

Explanation:

7 0

3 years ago