Can someone please help me with this?--20 pts!

Chemistry

1 answer:

katrin2010 [14]3 years ago

3 0

Answer:

Compound B is ionic. The electronegativity difference is 2.2, which can be determined by subtracting the electronegativity of Element Y from that of Element Z. Electronegativity differences greater than 1.7 indicate ionic bonds.

Hope that helps.

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Give the products of the reaction of butanal, with: (a) sodium borohydride, in methanol (b) hydrogen cyanide, with catalytic cya

miss Akunina [59]

Answer:

Answers are given below

Explanation:

(a) Aldehyde groups are reduced by sodium borohydride in methanol to give alcohol.

So, butanal produces butanol on reaction with sodium borohydride in methanol.

(b) Aldehyde forms cyanohydrin when they are treated with HCN with catalytic cyanide.

(d) Aldehyde produces acetal with methanol and a trace amount of acid catalyst.

(e) Aldehyde gives condensation reaction with $CH_{3}CH_{2}NH_{2}$ to produce imine.

Structures of products for the given reaction has been shown below.

4 0

3 years ago

Suppose 'A' is a liquid aromatic compound with molecular weight 78 and burns with sooty flame. a.Give the name of the compound '

Oliga [24]

Aromatic compounds are compounds that contain carbon-carbon multiple bonds.

The question did not mention that a heteroatom is present in the compound so we can assume that there is none of such. In that case, the compound contains only hydrogen and carbon.

So,

(CH)n = 78

where n is the number of each atom present.

(12 +1)n = 78

n = 78/13

n = 6

The molecular formula of the compound is C6H6

When C6H6 is treated with .conc.HNO3/conc.H2SO4 the compound shown in image 1 is formed. The reaction occurs at the C-C multiple bond.

When C6H6 is reacted with chlorine in the presence of sunlight, hexachlorobenzene (shown in image 2 attached) is formed.

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