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2 years ago

Alkenes can be hydrated via the addition of borane to yield alcohols with non-Markovnikov regiochemistry.

Chemistry

1 answer:

galina1969 [7]2 years ago

8 0

Answer:

The given statement is true.

Explanation:

Initially, the addition of borane to the alkene takes place in the form of a concerted reaction owing to the dissociation of the bond and subsequent formation, which occurs at a similar time. After that the Anti Markovnikov supplementation of boron takes place. The addition of this atom takes place with the less substituted carbon of the alkene that then substitutes the molecule of hydrogen on the more substituted carbon.

Then through the donation of a pair of electrons from the hydrogen peroxide ion, the process of oxidation takes place resulting in the formation of trialkylborane. After this realignment of an R group with its pair of bonding, electrons take place with adjacent oxygen resulting in the withdrawal of a hydroxide ion. Eventually, the trialkylborate reacts with the aqueous NaOH to generate alcohol and sodium borate as the side product.

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Upper n subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper N upper H subscript 3 (g). At equilibrium, th

artcher [175]

Answer:

The equilibrium constant is:

$k_c=0.0030M^{-2}$

Explanation:

The correct equation is:

N₂(g) + 3H₂(g) ⇄ 2NH₃(g)

Thus, with the equilibrium concentrations you can calculate the equilibrium constant, Kc.

The equation for the equilibrium constant is:

$k_c=\dfrac{[NH_3]^2}{[N_2]\cdot [H_2]^3}$

Substituting:

$k_c=\dfrac{(0.105M)^2}{(1.1M)\cdot (1.50M)^3}$

$k_c=0.0030M^{-2}$

6 0

3 years ago

A galvanic cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). W

Agata [3.3K]

Answer : The 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Explanation :

Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the voltaic cell or electrochemical cell.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

We are taking the value of standard reduction potential form the standard table.

$E^0_{[Ag^{+}/Ag]}=+0.80V$

$E^0_{[Cu^{2+}/Cu]}=+0.34V$

In this cell, the component that has lower standard reduction potential gets oxidized and that is added to the anode electrode. The second forms the cathode electrode.

The balanced two-half reactions will be,

Oxidation half reaction (Anode) : $Cu(s)\rightarrow Cu^{2+}(aq)+2e^-$

Reduction half reaction (Cathode) : $Ag^{+}(aq)+e^-\rightarrow Ag(s)$

Thus the overall reaction will be,

$Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)$

From this we conclude that, 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Hence, the 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

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3 years ago

Which are examples of equilibrium? Check all that apply.

NeX [460]

The equilibrium means that amount that are coming equals the amount that are going.
So the correct answers are
2. A person's income and expenses are equal every month.
3. The pressure exerted on the inside of a balloon by the gas inside is equal to the pressure exerted on the outside of the balloon by the atmosphere.

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3 years ago

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2 years ago