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2 years ago

In a star, nuclear fusion occurs in the

Chemistry

2 answers:

Viktor [21]2 years ago

6 0

Answer:

core

Explanation:

slega [8]2 years ago

5 0

Answer:

A. Core

Explanation:

The collisions which occur between the hydrogen atoms starts to heat the gas in the cloud. Once the temperature reaches 15,000,000 degrees Celsius, nuclear fusion takes place in the center, or core, of the cloud. The tremendous heat given off by the nuclear fusion process causes the gas to glow creating a protostar.

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At a soccer game, a player kicks the ball. It leaves the ground as it travels across the field. Then, it comes back to the groun

otez555 [7]

Answer:

Explanation:

the gravitational force is a big play.

8 0

2 years ago

Read 2 more answers

Two litres of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 litres. How m

nlexa [21]

Answer:

The work done and heat absorbed are both -8,1 kJ

Explanation:

The work done in an isobaric process is defined as:

W = -P (Vf - Vi)

Where P is pressure ( 10 atm)

Vf = 10 L

Vi = 2 L

Thus, W = -80 atm×L ≡ -8,1 kJ

This is the work done in expansion of the gas. As the gas remains at the same temperature, there is no change in internal energy doing that all work was absorbed as heat.

I hope it helps!

4 0

3 years ago

A sample of argon gas has a volume of 795 mL at a pres-sure of 1.20 atm and a temperature of 116 ∘C. What is the final volume of

jek_recluse [69]

Answer: The volume when the pressure and temperature has changed is $1.6\times 10^2mL$

Explanation:

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

Let us assume:

$P_1=1.20atm\\V_1=795mL\\T_1=116^oC=[116+273]K=389K\\P_2=0.55atm\\V_2=?mL\\T_2=75^oC=[75+273]K=348K$

Putting values in above equation, we get:

$\frac{1.20atm\times 795mL}{389K}=\frac{0.55atm\times V_2}{348K}\\\\V_2=\frac{1.20\times 795\times 348}{0.55\times 389}=1.6\times 10^3mL$

Hence, the volume when the pressure and temperature has changed is $1.6\times 10^2mL$

5 0

3 years ago

Which of the following represents the relative charge of proton

Snowcat [4.5K]

You’ve not put anything below so I’m not sure what the options are but the relative charge of a proton is +1

8 0

2 years ago

Please i need help ……

nasty-shy [4]

Answer:

Explanation:

(l) means liquid

(s) means solid

(g) means gaseous

I hope this helped [:

3 0

2 years ago