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mart [117]
3 years ago
9

Is w =15z direct variation

Mathematics
1 answer:
Cloud [144]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

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_________________ please help!!!!!!!
jeka94

Answer:

The answer would be C)5

Step-by-step explanation:

The unknown triangle is half of the size of the original triangle, The right side measurement basically hints to the actual answer.

5 0
3 years ago
Please help i need this quick ill give brainlyiest
PIT_PIT [208]
What the that needs to be solved
3 0
2 years ago
Formula for triangle are
Greeley [361]

The formula for a triangle:

Base times height divided by 2

Equation Form:

b×h÷2

6 0
2 years ago
find the coordinates of the vertex of the following parabola algebraically. write your answer as an (x,y) point..y=x²+9
Alexandra [31]

Explanation:

using the parabola formula:

y = a(x-h)² + k²

vertex = (h, k)

We are given a parebola equation of: y = x²+9

comparing both equations to get the vertex:

y = y

a = 1

(x-h)² = x²

x² = (x + 0)²

(x-h)² = (x + 0)²

h = 0

+k = +9

k = 9

The vertex of the parabola as (x, y): (0, 9)

3 0
1 year ago
Find the distance between (-5,6)and (3,2).
skad [1K]

Answer:

\displaystyle d = 4\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formulas]:                                                     \displaystyle d = \sqrt{(3+5)^2+(2-6)^2}
  2. [Distance] [√Radical] (Parenthesis) Add/Subtract:                                       \displaystyle d = \sqrt{(8)^2+(-4)^2}
  3. [Distance] [√Radical] Evaluate exponents:                                                    \displaystyle d = \sqrt{64+16}
  4. [Distance] [√Radical] Add:                                                                             \displaystyle d = \sqrt{80}
  5. [Distance] [√Radical] Simplify:                                                                         \displaystyle d = 4\sqrt{5}
6 0
3 years ago
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