note-Unlike the planetary model, our model view is that the electrons move around the nucleus in an electron cloud. Modern atomic theory states that the atom is a diffuse cloud surrounding a small, dense nucleus. Identify which particle is in the nucleus. note-Neutron is a particle in the nucleus.
The answer is
h: sB and Sb
hd : sb
hr : SB
<h2>Question:</h2>
In this circuit the resistance R1 is 3Ω, R2 is 7Ω, and R3 is 7Ω. If this combination of resistors were to be replaced by a single resistor with an equivalent resistance, what should that resistance be?
Answer:
9.1Ω
Explanation:
The circuit diagram has been attached to this response.
(i) From the diagram, resistors R1 and R2 are connected in parallel to each other. The reciprocal of their equivalent resistance, say Rₓ, is the sum of the reciprocals of the resistances of each of them. i.e

=>
------------(i)
From the question;
R1 = 3Ω,
R2 = 7Ω
Substitute these values into equation (i) as follows;


Ω
(ii) Now, since we have found the equivalent resistance (Rₓ) of R1 and R2, this resistance (Rₓ) is in series with the third resistor. i.e Rₓ and R3 are connected in series. This is shown in the second image attached to this response.
Because these resistors are connected in series, they can be replaced by a single resistor with an equivalent resistance R. Where R is the sum of the resistances of the two resistors: Rₓ and R3. i.e
R = Rₓ + R3
Rₓ = 2.1Ω
R3 = 7Ω
=> R = 2.1Ω + 7Ω = 9.1Ω
Therefore, the combination of the resistors R1, R2 and R3 can be replaced with a single resistor with an equivalent resistance of 9.1Ω
A skill set is explicitly taught or an activity is completed
To solve this problem it is necessary to apply the concepts related to the Rotational Force described from the equilibrium and Newton's second law.
When there is equilibrium, the Force generated by the tension is equivalent to the Force of the Weight. However in rotation, the Weight must be equivalent to the Centrifugal Force and the tension, in other words:

Where
Angular velocity is equal to the Period, at this case Earth's period
Radius of the Earth
m = mass
= Force of Tension
Newton's second law
Replacing and re-arrange to find the Tension we have,






Therefore when Sneezy is on the equator he is in a circular orbit with a Force of tension of 503.26N