R 1,2 = 27.5 + 33.0 = 60.5 Ohms
1/ R 1,2,3 = 1/ 60.5 + 1 / 22 = 82.5 / 1331
R 1, 2, 3 = 1331 / 82.5 = 16.13 Ohms
I = U / R
I = 9 V / 16.13 Ohms = 0.557 A ≈ 0.56 A
Answer: C ) 0.56 Amps
Noise does not affect the digital signal making it more reliable
As proton is heavier then electron, and electrostatic force is directly proportional to mass, so it would be greater and direction would be changed 'cause of different charges.
In short, Your Answer would be Option 4
Hope this helps!
A) The power delivered to the lines is

And the voltage at which the lines work is

Since the power delivered is the product between the voltage and the current:

We can find the current flowing in the lines:

b) The voltage change along each line can be found by using Ohm's law:

c) The power wasted as heat along each line is given by:

And since we have 2 lines, the total power wasted as heat in both lines is