the answer is c in question 7
Answer : The specific heat capacity of the alloy 
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.


where,
= specific heat of alloy = ?
= specific heat of water = 
= mass of alloy = 21.6 g
= mass of water = 50.0 g
= final temperature of system = 
= initial temperature of alloy = 
= initial temperature of water = 
Now put all the given values in the above formula, we get


Therefore, the specific heat capacity of the alloy 
They are incline hope this helps!
The answer would be 46.482 because you multiply 18.3 by 2.54 because for every inch you get 2.54 centimeters