Answer:
"Both students are correct. When light is traveling through small openings, solids, liquids, gases, or a vacuum, it behaves like a wave. When it interacts with matter, it acts like a stream of particles."
Explanation:
just got it right 
 
        
             
        
        
        
Answer:
Part a)

Part b)

So density of atmosphere at Martian Surface is very less than the density at Earth.
Explanation:
Part a)
As per ideal gas equation we know that

here we know that Martian atmosphere is equivalent to that of carbon
so we will have


now we will have


Part b)
Now for the earth surface the density of air is given for


so we will have



So density of atmosphere at Martian Surface is very less than the density at Earth.
 
        
             
        
        
        
Answer:
nothing interest, i just hate that part i love only the calculations 
 
        
                    
             
        
        
        
Answer:
<em>To reverse the direction of an electric current, we simply reverse the voltage either automatically with the help of some switching circuitry or manually by changing the voltage source terminals connection.  </em>
Explanation:
For electric current to flow, there must be a potential difference, usually referred to as the voltage. The electric current flow is analogous to the flow of water under the action of a pump, through a series of pipe connections. The voltage is similar to the driving action of the pump, and current flows the same way water flows. The resistance due to drag on the pipe wall is equivalent to electric resistance. For current to flow in the reverse direction, the voltage or rather, the potential difference is changed, causing the current to flow in the opposite direction. This can be done by switching the terminals of the voltage source, or by automatic means. The automatic switching can be done with a transistor based circuitry.
 
        
             
        
        
        
Answer:
Pressure will be 
Explanation:
We have given mass of the women m = 65 kg 
Radius of the heels r = 0.578 cm = 0.00578 m
We have to find the pressure 
We know that pressure is given by 

So force F = mg = 65×9.8 = 637 N
Area 
So pressure 