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kotegsom [21]
3 years ago
15

What forms of energy are involved when snow on a mountain breaks loose, resulting in an avalanche?

Physics
2 answers:
Lynna [10]3 years ago
7 0
1. Potential energy.
2.kinetic energy.
Gnom [1K]3 years ago
6 0

Answer:

1. Potential energy.

2.kinetic energy.

Explanation:

took the test and it was right

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4. A free body diagram of a brick on
Otrada [13]

Answer:

bn

nnnnnnnnn

Explanation:

8 0
2 years ago
Which would hit the ground first if dropped from the same height in a vacuum—a feather or a metal bolt?
vovikov84 [41]
They hit the ground at the same time
4 0
2 years ago
The mass of a brick is 2kg. Find the mass of water displaced by it when it is completely immersed in water. (Density of the bric
hjlf

Answer:

2000g

Explanation:

volume=mass/density

=2000/2.5

=800cm³

mass=density×volume

=800×2.5

=2000g

4 0
2 years ago
Nerve impulses in a human body travel at a speed of about 100 m/s. Suppose a person accidentally steps barefoot on a pebble. Abo
PilotLPTM [1.2K]

Answer:

The time required by the impulse to travel from foot to brain equals 0.019 seconds

Explanation:

For uniform motion the distance, speed, time are related by the equation

Distance=Speed\times time

In our case since the person is 1.90 meters tall so the nerve impulse will have to cover a distance of 1.90 meters at a speed of 100 m/s.

Hence the time required for the impulse to travel from foot to the brain can be calculated as

time=\frac{Distance}{speed}\\\\\therefore time=\frac{1.90m}{100m/s}=0.019seconds

4 0
3 years ago
A sound is recorded at 19 decibels. What is the intensity of the sound?
aalyn [17]

Answer:

79·433 × 10^{-12} W/m²

Explanation:

Given intensity of sound in decibels is 19

Formula for intensity of sound in decibels is

<h3>I_{1} = 10 × ㏒(I ÷ I_{0})</h3>

where

I_{1} is the intensity of sound measured in decibels

I is the intensity of sound measured in W/m²

I_{0} is the intensity of the sound that is taken as standard and it's value is equal to 10^{-12} W/m²

By applying the formula

19 = 10 × ㏒(I ÷ I_{0})

⇒ 1·9 = ㏒(I ÷ I_{0})

⇒ antilog(1·9) = I ÷ I_{0}

⇒ 79·433 = I ÷ 10^{-12}

⇒ I = 79·433 × 10^{-12} W/m²

∴ Intensity of sound = 79·433 × 10^{-12} W/m²

4 0
3 years ago
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