Answer:
True
Explanation:
If there's no preference over the string case (upper case or lower case), one can convert both strings to upper case or to lowercase and then compare the converted strings to test if they're equal or not.
An Illustration is
string a = "Boy"
string b = 'bOy"
if(a.ToUpper() == b.ToUpper() || a.ToLower() == b.ToLower())
{
Print "Equal Strings"
}
else
{
Print "Strings are not equal";
}
The above will first convert both strings and then compare.
Since they are the same (after conversion), the statement "Equal Strings" will be printed, without the quotes
A little confused by the wording of the problem, but it is true that an object can have a negative acceleration and be speeding up in the negative direction… so I’d go with True
"increments of 8" means the major divisions are 0,8,16,24 ?
<span>x axis, calculate the moment arms from 0 </span>
<span>3x4, 2x12, 1x20 </span>
<span>from an arbitrary C </span>
<span>3(c-4) + 2(c-12) + (c-20) = 0 </span>
<span>3c - 12 + 2c -24 + c - 20 = 0 </span>
<span>6c = 56 </span>
<span>c = 9.33 </span>
<span>y axis </span>
<span>3x3, 1x12, 2x20 </span>
<span>3(c-4) + 1(c-12) +2 (c-20) = 0 </span>
<span>3c - 12 + c - 12 + 2c - 40 = 0 </span>
<span>6c = 64 </span>
<span>c = 10.67 </span>
<span>so center is x = 9.33, y = 10.67 </span>
Naturally occurring or organic substances and molecules such as cell membranes are combination structures.
<h3>What are combination structures?</h3>
Combination structures are substances which result from the combination of two or more different substances.
<h3>What are some natural combination structures?</h3>
Natural combination structures are found everywhere in the natural world.
Examples of combination structures are organic compounds and molecules including:
- Cell membranes composed of lipids, proteins and carbohydrates.
Therefore, organic substances and molecules such as cell membranes are combination structures.
Learn more about organic structures at: brainly.com/question/24523369
The driver speeds up with acceleration <em>a</em> so that
35 m/s = 15 m/s + <em>a</em> (10.0 s)
Solve for <em>a</em> :
20 m/s = <em>a</em> (10.0 s)
<em>a</em> = (20 m/s) / (10.0 s)
<em>a</em> = 2 m/s²
