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Romashka [77]
3 years ago
11

We can use energy principles to make ____ predictions.

Physics
1 answer:
stira [4]3 years ago
5 0
Compatible and speedy
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6. What is the resultant force on each car below? Remember TWO pieces of
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Explanation:

In first case, the forces on LHS and on RHS is the same i.e. 3 N. The force acting on the car is balanced force. As a result, the car will not move at all.

In second case,

Force on RHS = 2000 N

Force on LHS = -6000 N

Net force acting on it is given by :

F = 2000+(-6000)

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Hence, this is the required solution.

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How many estimates are used in the calculation of depreciation?
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Answer:

Two estimates

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There are mainly two estimates used in the calculation of depreciation such as the useful life and the salvage value of an asset. The salvage value is defined as the predicted amount that will be obtained by a company from an asset when it is disposed at the end of the useful life of the particular asset. On the other hand, the useful life commonly refers to the estimation of how long the asset is useful for the company. This is different from the lifespan of the asset.  

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3 years ago
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A DC motor's magnet has a magnetic field that ____ the wire loop's magnetic field, therefore causing the loop to rotate.
jek_recluse [69]

b. deflects. A DC motor's magnet has a magnetic field that <em><u>deflects</u></em> the wire loop's magnetic field, therefore causing the loop to rotate.

When a conductor, through which an electric current passes, is immersed in a magnetic field, it experiences a deflects force according to the Law of Lorentz creating as result that the loop rotate.

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3 years ago
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A circular loop of diameter 10 cm, carrying a current of 0.20 A, is placed inside a magnetic field B⃗ =0.30 Tk^. The normal to t
arlik [135]

Answer:

The magnitude of the torque on the loop due to the magnetic field is 4.7\times10^{-4}\ N-m.

Explanation:

Given that,

Diameter = 10 cm

Current = 0.20 A

Magnetic field = 0.30 T

Unit vectorn=-0.60\hat{i}-0.080\hat{j}

We need to calculate the torque on the loop

Using formula of torque

\tau=NIAB\sin\theta

Where, N = number of turns

A = area

I = current

B = magnetic field

Put the value into the formula

\tau=1\times0.20\times\pi\times(5\times10^{-2})^2\times0.30\times\sin90^{\circ}

\tau=4.7\times10^{-4}\ N-m

Hence, The magnitude of the torque on the loop due to the magnetic field is 4.7\times10^{-4}\ N-m.

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