Ask question

Ask question

All categories

3 years ago

11

We can use energy principles to make ____ predictions.

1 answer:

stira [4]3 years ago

5 0

Compatible and speedy

You might be interested in

You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced 7.5 x

Blizzard [7]

Complete Question

You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced $7.5 * 10^{-3}$ meters apart. However, by placing a piece of crystal in one of the slits, you are able to make it so that the rays of light that travel through the two slits are Ï out of phase with each other (that is to say, Ao,- ). If you observe that on a screen placed 4 meters from the two slits that the distance between the bright spot closest to center of the pattern is 1.5 cm, what is the wavelength of the laser?

Answer:

The wavelength is $\lambda = 56250 nm$

Explanation:

From the question we are told that

The distance of slit separation is $d = 7.5 *10^{-3} \ m$

The distance of the screen is $D = 4 \ m$

The distance between the bright spot closest to the center of the interference is $k = 1.5 \ cm = 0.015 \ m$

Generally the width of the central maximum fringe produced is mathematically represented as

$y = 2 * k = \frac{ D * \lambda}{d}$

=> $2 * 0.015 = \frac{ \lambda * 4}{ 7.5 *10^{-3}}$

=> $\lambda = 56250 *10^{-9} \ m$

=> $\lambda = 56250 nm$

7 0

3 years ago

A small airplane has to reach a speed if 27.8 m/s to takeoff. It can accelerate at 2.00 m/s^2. What is the minimal length of run

pickupchik [31]

Using the constant acceleration formula v^2 = u^2 + 2as, we can figure out that it would take a distance of 193.21m to reach 27.8m/s

3 0

3 years ago

An airliner arrives at the terminal, and its engines are shut off. The rotor of one of the engines has an initial clockwise angu

Ilia_Sergeevich [38]

(a) 1200 rad/s

The angular acceleration of the rotor is given by:

$\alpha = \frac{\omega_f - \omega_i}{t}$

where we have

$\alpha = -80.0 rad/s^2$ is the angular acceleration (negative since the rotor is slowing down)

$\omega_f$ is the final angular speed

$\omega_i = 2000 rad/s$ is the initial angular speed

t = 10.0 s is the time interval

Solving for $\omega_f$ , we find the final angular speed after 10.0 s:

$\omega_f = \omega_i + \alpha t = 2000 rad/s + (-80.0 rad/s^2)(10.0 s)=1200 rad/s$

(b) 25 s

We can calculate the time needed for the rotor to come to rest, by using again the same formula:

$\alpha = \frac{\omega_f - \omega_i}{t}$

If we re-arrange it for t, we get:

$t = \frac{\omega_f - \omega_i}{\alpha}$

where here we have

$\omega_i = 2000 rad/s$ is the initial angular speed

$\omega_f=0$ is the final angular speed

$\alpha = -80.0 rad/s^2$ is the angular acceleration

Solving the equation,

$t=\frac{0-2000 rad/s}{-80.0 rad/s^2}=25 s$

6 0

2 years ago

What weather would create the weakest surfing waves?

ella [17]

Its B hope I could help

5 0

2 years ago

Calculate the total displacement if a toy car starts at 0 moves 5cm to the left then 8cm to the right then 3 cm to the left

never [62]

It’s a total of 16 cm because it starts at 0 moves then moves to left then the right then the left

6 0

3 years ago