Mateo and Jackie were on a playground rolling some different-sized balls to get them to crash. They used a tennis ball (the same
mass) in both crashes. They tried two soccer balls—a pink one (more mass) for Crash 1 and a blue one (less mass) for Crash 2.
Mateo and Jackie want to know what happened to the tennis ball. Use information from the diagram to answer.
In which crash did the tennis ball experience a stronger force? How do you know?
a
Crash 1; the force on the soccer ball was stronger in this crash, so the force on the tennis ball was also stronger.
b
There was no force on the tennis ball. In each crash, only the soccer ball experienced a force.
c
It was the same in both crashes. The soccer ball changed speed by the same amount in each crash, so the force on the tennis ball was the same both times.
d
The diagram doesn’t tell you anything about the force on the tennis ball. It only gives information about the force on the soccer balls.
Mateo and Jackie want to know what happened to the tennis ball. Use information from the diagram to answer.
In which crash did the tennis ball experience a stronger force? How do you know?
a
Crash 1; the force on the soccer ball was stronger in this crash, so the force on the tennis ball was also stronger.
b
There was no force on the tennis ball. In each crash, only the soccer ball experienced a force.
c
It was the same in both crashes. The soccer ball changed speed by the same amount in each crash, so the force on the tennis ball was the same both times.
d
The diagram doesn’t tell you anything about the force on the tennis ball. It only gives information about the force on the soccer balls.
1 answer:
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Answer
given,
length of bar = 80 cm
mass of the bar = 10 kg
smaller mass = 4 kg
distance = 20 cm
taking moment about B
difference between two scale = 8 - 6
= 2 N
Explanation:
(1). Formula to calculate the potential difference is as follows.
=
=
=
=
= 38.7 volts
Therefore, magnitude of the potential difference between the two spheres is 38.7 volts.
(2). Now, formula to calculate the energy stored in the capacitor is as follows.
E =
=
=
Thus, the electric-field energy stored in the capacitor is .
Answer:
C).
Explanation:
As we know that capacitance of a given capacitor is
now we know that energy stored in the capacitor plates
here if all the dimensions of the capacitor plate is doubled
then in that case
here area becomes 4 times on doubling the radius and the distance between the plates also doubles
So new capacitance is now
so capacitance is doubled
now the final energy stored between the plates of capacitor is given as
so the final energy is