Mateo and Jackie were on a playground rolling some different-sized balls to get them to crash. They used a tennis ball (the same
mass) in both crashes. They tried two soccer balls—a pink one (more mass) for Crash 1 and a blue one (less mass) for Crash 2.
Mateo and Jackie want to know what happened to the tennis ball. Use information from the diagram to answer.
In which crash did the tennis ball experience a stronger force? How do you know?
a
Crash 1; the force on the soccer ball was stronger in this crash, so the force on the tennis ball was also stronger.
b
There was no force on the tennis ball. In each crash, only the soccer ball experienced a force.
c
It was the same in both crashes. The soccer ball changed speed by the same amount in each crash, so the force on the tennis ball was the same both times.
d
The diagram doesn’t tell you anything about the force on the tennis ball. It only gives information about the force on the soccer balls.
Mateo and Jackie want to know what happened to the tennis ball. Use information from the diagram to answer.
In which crash did the tennis ball experience a stronger force? How do you know?
a
Crash 1; the force on the soccer ball was stronger in this crash, so the force on the tennis ball was also stronger.
b
There was no force on the tennis ball. In each crash, only the soccer ball experienced a force.
c
It was the same in both crashes. The soccer ball changed speed by the same amount in each crash, so the force on the tennis ball was the same both times.
d
The diagram doesn’t tell you anything about the force on the tennis ball. It only gives information about the force on the soccer balls.
1 answer:
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Answer:
a.) magnitude __49.7__ unit(s)
b.) direction __123.6°_ counterclockwise from the +x axis
Explanation:
Let Vector is v
x-component of Vector v = x = -27.5 units (minus sign indicate that x-component is along the minus x-axis )
y-component of Vector v = y = 41.4 units
Magnitude of v = ?
Direction of v = ?
To find the magnitude of the vector
v =
v =
v = 49.7 units
To find direction
θ = tan⁻¹(y/x)
θ = tan⁻¹(41.4/-27.5)
θ = -56.4°
This Angle is in the clockwise direction with respect to -x axis.
We need to find Angle counterclockwise from the +x axis.
So,
θ = 180° - 56.4°
θ = 123.6°
The given vector is in 2nd quadrant