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Vesna [10]
3 years ago
15

A jet of water squirts out horizontally from a

Physics
1 answer:
Triss [41]3 years ago
6 0

Answer:

9.54 cm

Explanation:

The water is in free fall after it leaves the tank.  The time it takes to land is:

Δy = v₀ t + ½ at²

1.23 m = (0 m/s) t + ½ (9.8 m/s²) t²

t = 0.501 s

Therefore, the horizontal velocity is:

v = 0.685 m / 0.501 s

v = 1.37 m/s

Using Bernoulli equation, where point 1 is the surface of the water and point 2 is the exit of the tank:

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

Since P₁ = P₂, and v₁ = 0:

ρgh₁ = ½ ρ v₂² + ρgh₂

gh₁ = ½ v₂² + gh₂

gh = ½ v₂²

h = v₂²/(2g)

Plugging in:

h = (1.37 m/s)² / (2 × 9.8 m/s²)

h = 0.0954 m

h = 9.54 cm

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<h3>What is resultant displacement?</h3>

The resultant displacement of an object is the change in position of the object. It can be described as the shortest distance connecting the final position of the object to the initial position of the object.

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Thus, at the end of the walk, the person's resultant displacement is 495.1 m at 63⁰ south of west.

Learn more about resultant displacement here: brainly.com/question/13309193

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Please find the answer in the explanation.

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