Answer:
<u> </u><u>»</u><u> </u><u>Image</u><u> </u><u>distance</u><u> </u><u>:</u>
- v is image distance
- u is object distance, u is 10 cm
- f is focal length, f is 5 cm
<u> </u><u>»</u><u> </u><u>Magnification</u><u> </u><u>:</u>
• Let's derive this formula from the lens formula:
» Multiply throughout by fv
• But we know that, v/u is M
- v is image distance, v is 10 cm
- f is focal length, f is 5 cm
- M is magnification.
<u> </u><u>»</u><u> </u><u>Nature</u><u> </u><u>of</u><u> </u><u>Image</u><u> </u><u>:</u>
- Image is magnified
- Image is erect or upright
- Image is inverted
- Image distance is identical to object distance.
1. he traveled a total of 24 miles
2. peter is not moving between 10 and 30 minutes
Answer:
34883.7
Explanation:
Primero hay que convertir las dos unidades a la misma unidad-cm-
3km- 300000 cm
86mm- 8.6mm
Después hay que dividir
300000/8.6= 34883.7209302 ~ 34883.7
Answer:
if the frequency is double, the wavelength is only half as long
Explanation:
Answer:
<em>10.90km</em>
Explanation:
Magnitude of the total displacement is expressed using the equation
d = √dx²+dy²
dx is the horizontal component of the displacement
dy is the vertical component of the displacement
dy = -6.7sin27°
dy = -6.7(0.4539)
dy = -3.042
For the horizontal component of the displacement
dx = -4.5 - 6.7cos27
dx = -4.5 -5.9697
dx = -10.4697
Get the magnitude of the bicyclist's total displacement
Recall that: d = √dx²+dy²
d = √(-3.042)²+(-10.4697)²
d = √9.2538+109.6146
d = √118.8684
<em>d = 10.90km</em>
<em>Hence the magnitude of the bicyclist's total displacement is 10.90km</em>
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