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Paul [167]
4 years ago
12

How long does it take for a truck accelerating at 1.5 m/s^2 to got from rest to 75 km/hr

Physics
1 answer:
Free_Kalibri [48]4 years ago
6 0

Answer:

t = 13.9s

Explanation:

u = 0 m/s

v = 75 km/h

= 20.83 m/s

a = 1.5 m/s²

Using

v = u + at

20.83 = 0 + 1.5t

t = 13.9s

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2. A ball is released from a vertical height of 20 cm. It rolls down a "perfectly
Paraphin [41]

Answer:

20 cm

Explanation:

Given that a ball is released from a vertical height of 20 cm. It rolls down a "perfectly frictionless" ramp and up a similar ramp. What vertical height on the second ramp will the ball reach before it starts to roll back down?

Since it is perfectly frictionless, the Kinetic energy in which the ball is rolling will be equal to the potential energy at the edge of the ramp.

Therefore, the ball will reach 20 cm before it starts to roll back down.

7 0
3 years ago
In a ballistics test, a 52g bullet hits a sand bag and stops after moving 1.34 m. If the initial bullat
olya-2409 [2.1K]

Answer:

Friction force on the bullet is 58.7 N opposite to its velocity

Explanation:

As we know that initial speed of the bullet is 55 m/s

after travelling into the sand bag by distance d = 1.34 m it comes to rest

so final speed

v_f = 0

now we can use kinematics top find the acceleration of the bullet

v_f^2 - v_i^2 = 2 a d

so we have

0 - 55^2 = 2(a)(1.34)

a = -1128.7 m/s^2

now by Newton's II law we know that

F = ma

so we have

F = (0.052)(-1128.7)

F = -58.7 N

8 0
3 years ago
17. Calculate the amount of gravitational potential energy at the top of one 4 points hill. The mass of the coaster is 500 kg. T
MissTica

Answer: D. 292,338 J

This is the correct answer :)

4 0
3 years ago
Up to a point, the elongation of a spring is directly proportional to the force applied to it. Once you extend the spring more t
olga2289 [7]

The force result in stretching the spring 10.0 centimeters is 2.5N.

<h3>What is Hooke's law?</h3>

If a spring is stretched from its equilibrium position, then a force with magnitude proportional to the increase in length from the equilibrium length is pulling each end.

F = kx

where k is the proportionality constant called the spring constant or force constant.

Up to a point, the elongation of a spring is directly proportional to the force applied to it. Once you extend the spring more than 10.0 centimeters, however, it no longer follows that simple linear rule.

Let the spring constant be very low 0.04N/m

The force applied is

F = 10 cm / 0.04

F = 0.1 m  / 0.04

F = 2.5 N

Thus, the force result in stretching the spring 10cm is 2.5 N.

Learn more about hooke's law.

brainly.com/question/13348278

#SPJ1

5 0
2 years ago
What do ocean waves and sound waves have in common?
Maksim231197 [3]
D. Both exhibit the same particle-to-particle interaction.Because disturbance is propagated with the help of particles. Other than this,[ <span>light waves are electromagnetic waves. ocean waves and sound waves are mechanical waves. they are able to transfer energy. electromagnetic wave and ocean waves are transverse waves while sound waves are the longitudinal wave. they show wave properties: reflection, refraction, diffraction, interference, and plane-polarization. longitudinal waves such as sound waves cannot be plane-polarized]. The one in the box shows different examples of waves with their examples. Hope it helps.</span>
7 0
3 years ago
Read 2 more answers
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