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dusya [7]
2 years ago
7

Paula ran a total of 72meters directly toward school at a constant velocity. She ran one-third of that distance in 8seconds. Wha

t was her velocity?
Physics
1 answer:
Nezavi [6.7K]2 years ago
3 0

Answer:

3 meters per second

Explanation:

72 divided by 3= 24 meters in 8 seconds

24/8= 3, so 3 meters per second

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daser333 [38]

Answer:

I think D sorry if I'm wrong

6 0
2 years ago
What do you do if you approach a railroad crossing with a crossbuck sign that has no lights or gates
miv72 [106K]
Proceed with caution before crossing
3 0
3 years ago
if a train starts from rest and attains a velocity of 100m/s in 25 seconds. calculate the acceleration produced by the train.​
stira [4]
-4 km/s2

Explanation:
0-100/25
-100/25
-4
5 0
3 years ago
One string of a certain musical instrument is 70.0 cm long and has a mass of 8.79 g . It is being played in a room where the spe
Svetach [21]

To solve this problem we will apply the concepts of linear mass density, and the expression of the wavelength with which we can find the frequency of the string. With these values it will be possible to find the voltage value. Later we will apply concepts related to harmonic waves in order to find the fundamental frequency.

The linear mass density is given as,

\mu = \frac{m}{l}

\mu = \frac{8.79*10^{-3}}{70*10^{-2}}

\mu = 0.01255kg/m

The expression for the wavelength of the standing wave for the second overtone is

\lambda = \frac{2}{3} l

Replacing we have

\lambda = \frac{2}{3} (70*10^{-2})

\lambda = 0.466m

The frequency of the sound wave is

f_s = \frac{v}{\lambda_s}

f_s = \frac{344}{0.768}

f_s = 448Hz

Now the velocity of the wave would be

v = f_s \lambda

v = (448)(0.466)

v = 208.768m/s

The expression that relates the velocity of the wave, tension on the string and linear mass density is

v = \sqrt{\frac{T}{\mu}}

v^2 = \frac{T}{\mu}

T= \mu v^2

T = (0.01255kg/m)(208.768m/s)^2

T = 547N

The tension in the string is 547N

PART B) The relation between the fundamental frequency and the n^{th} harmonic frequency is

f_n = nf_1

Overtone is the resonant frequency above the fundamental frequency. The second overtone is the second resonant frequency after the fundamental frequency. Therefore

n=3

Then,

f_3 = 3f_1

Rearranging to find the fundamental frequency

f_1 = \frac{f_3}{3}

f_1 = \frac{448Hz}{3}

f_1 = 149.9Hz

7 0
3 years ago
Prior to the Panama Canal, __________ was a major route between the Atlantic and Pacific oceans.
Bingel [31]
The Rio Grande was the major route prior to the Panama Canal.
3 0
3 years ago
Read 2 more answers
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