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konstantin123 [22]
2 years ago
7

Anyone.... help with this two questions...​

Physics
2 answers:
PSYCHO15rus [73]2 years ago
7 0

Answer:

what is the question

]

Explanation:

w

dlinn [17]2 years ago
4 0
Do you still need help
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A jogger runs at a constant rate of 10.0 m every 2.0 seconds. The jogger starts at the origin and runs in the positive direction
Elis [28]

Answer:

(a) 25 m

(b) 75 m

Explanation:

Given that the jogger runs at a constant rate of 10.0 m every 2.0 seconds.

So, the speed of the jogger,

v=\frac{10}{2}=5m/s\;\cdots(i)

Let d be the distance covered by him in time, t s.

As distance=(speed) x (time)

So, d=vt

From equation (i)

\Rightarrow d=5t\;\cdots(ii)

As the jogger starts from origin, so, the distance, d, also represents the position of the jogger at the time t s.

The position-time graph has been shown.

(a) From equation (ii), for t=5.0 s

d=5\times 5=25 m

So, the jogger is at a distance of 25 m from the origin.

(b) Similarly, for t=15.0 s

d=5\times 15=75 m

So, the jogger is at a distance of 75 m from the origin.

8 0
3 years ago
A car's horn produces a constant frequency of 350 Hz as it passes by Suzy. What is the best estimate of the
Arada [10]

Answer:

330 Hz

Explanation:

edg2020

8 0
2 years ago
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Determine if the data are qualitative or quantitative.
Amanda [17]

Answer:

Qualitative, Quantitative, Qualitative, Quantitative, and Qualitative.

Explanation:

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Driving along a boring stretch of interstate in Illinois, you start experimenting using the average speed equation you learned i
astra-53 [7]
The average speed would be 33.29m/s.
The average speed equation is:

Average speed =  \frac{total distance}{total time}

First you will need to solve for the distance you traveled in each scenario. So we can solve this by getting the product of speed and the time traveled. 

Scenario 1:
Speed = 29m/s
Time = 120s
Distance = ?

Distance = (29m/s)(120s)
               = 3,480m

Scenario 2
Speed = 35m/s
Time = 300s
Distance = ? 

Distance = (35m/s)(300s)
               = 10,500m

Now that you have the distance of both, you can solve for your average speed. 

Average speed = \frac{total distance}{total time}
                                = \frac{3,480m+10,500m}{120s+300s}
                                = \frac{13,980m}{420s}
                                = 33.29m/s
5 0
3 years ago
What are the two major characteristics that change when air is heated and cooled ? How do these characteristics change the movem
sleet_krkn [62]
Two major characteristics that change when air is heated and cooled is the density and the direction of the air flow. They change the movement of the air by heated air rises and cooled air doesn't. 
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3 years ago
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