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PilotLPTM [1.2K]
3 years ago
13

4. Name three things that all games, no matter where they are played around the world, have in common.

Physics
2 answers:
oksian1 [2.3K]3 years ago
6 0

Answer:

the name of the games are goals, rules, challenges and interaction and mabe there can be more.

Explanation:

I hope this helped your day better this is the correct answer i got it correct on the test.

lilavasa [31]3 years ago
3 0

Answer:

Key components of games are goals, rules, challenge, and interaction.

Explanation:

Hope I helped.

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If you do 200 joules of work using a force of 50 newtons, over what distance was the force applied ?
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A hungry 177177 kg lion running northward at 75.575.5 km/hr attacks and holds onto a 32.332.3 kg Thomson's gazelle running eastw
ValentinkaMS [17]

Answer: 73.2 km/hr

Explanation:

This is a momentum conservation type of problem, here we need to use the fact that the initial momentum is equal to the final momentum.

Remember that the momentum is written as:

P = m*v

m = mass

v = velicity

At the beginning, we have:

A lion of 177 kg running at velocity of 75.5 km/hr

Then the momentum of the lion is P1 = 177 kg*75.5 km/hr= (13,363.5)kg*km/hr

The gazelle has a mass of 32.3 kg, and a velocity of 60.6 km/hr

Then the momentum of the gazelle is:

P2 = 32.3kg*60.6km/hr = 1,957.38 kg*km/hr

The total initial momentum is equal to P1 + P2, then we have:

P = 1,957.38 kg*km/hr + 13,363.5 kg*km/hr = 15,320.9 kg*km/hr

Now, after the lion catches the gazelle, we can think it as only one object moving with mass equal to the mass of the lion plus the mass of the gazelle and velocity V

Then the final momentum will be:

Pf = (177kg + 32.3kg)*V = 209.3kg*V

And this needs to be equal to the initial momentum, then:

209.3kg*V = 15,320.9 kg*km/hr

V = (15,320.9 kg*km/hr)/209.3kg = 73.2 km/hr

Then the final speed of the lion-gazelle system is 73.2 km/hr

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