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cupoosta [38]
3 years ago
5

Determine the launch speed of a horizontally launched cannonball that lands 26.3

Physics
1 answer:
nlexa [21]3 years ago
4 0

Answer:

The cannon has an initial speed of 13.25 m/s.

Explanation:

The launched cannonball is an example of a projectile. Thus, its launch speed can be determined by the application of the formula;

R = u\sqrt{\frac{2H}{g} }

Where: R is the range of the projectile, u is its initial speed, H is the height of the cliff and g is the gravitaty.

R = 26.3 m, H = 19.3 m, g = 9.8 m/s^{2}.

So that:

26.3 = u\sqrt{\frac{2*19.3}{9.8} }

(26.3)^{2} = u^{2} x \frac{38.6}{9.8}

691.69 =  u^{2} x \frac{38.6}{9.8}

u^{2} = \frac{691.69*9.8}{38.6}

   = \frac{6778.562}{38.6}

u^{2} = 175.6104

⇒ u = \sqrt{175.6104}

  = 13.2518

u = 13.25 m/s

The initial speed of the cannon is 13.25 m/s.

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