Question

Determine the launch speed of a horizontally launched cannonball that lands 26.3

Answer 1

Answer:

The cannon has an initial speed of 13.25 m/s.

Explanation:

The launched cannonball is an example of a projectile. Thus, its launch speed can be determined by the application of the formula;

R = u$\sqrt{\frac{2H}{g} }$

Where: R is the range of the projectile, u is its initial speed, H is the height of the cliff and g is the gravitaty.

R = 26.3 m, H = 19.3 m, g = 9.8 m/$s^{2}$.

So that:

26.3 = u$\sqrt{\frac{2*19.3}{9.8} }$

$(26.3)^{2}$ = $u^{2}$ x $\frac{38.6}{9.8}$

691.69 =  $u^{2}$ x $\frac{38.6}{9.8}$

$u^{2}$ = $\frac{691.69*9.8}{38.6}$

   = $\frac{6778.562}{38.6}$

$u^{2}$ = 175.6104

⇒ u = $\sqrt{175.6104}$

  = 13.2518

u = 13.25 m/s

The initial speed of the cannon is 13.25 m/s.