In the instructions for this problem I am told to distribute -4x^2. Why?
the order of operations is the order in which to simlify
if you look inside the parenthases, all like terms have been combined so the inside of parenthasees have already been simlified
expanding the exponents won't make it any easier so we move to distriubiting (or mulitplying)
so then the next step is mulitply -4x^2 by the trinomial
<span>In
the order of operations you must do problems inside parentheses first.
Why does multiplying monomials by polynomials change this? </span>multiplying monomails by polynomials does not change this
<span>Would the answer come out different if I did the work according to the order of operations?
no because distributing first is what you should do if you follow order of operations
</span>
Determine whether the stated conclusion is valid based on the given information. If not, write invalid. Explain your reasoning.
3. Given: If a number is divisible by 4, then the number is divisible by 2. 12 is divisible by four.
Conclusion: 12 is divisible by 2.
SOLUTION:
If p → q is a true statement and p is true, then q. Here, a number divisible 4 is divisible by 2 also and 12 is divisible by 4. So, 12 is divisible by 2 is a valid statement by the Law of Detachment.
ANSWER:
valid; Law of Detachment
4. Given: If Elan stays up late, he will be tired the next day. Elan is tired.
Conclusion: Elan stayed up late.
SOLUTION:
If p is true, then q is true, but q being true does not necessarily mean that p is true. Elan could be tired because he worked out. So, the statement is invalid.
ANSWER:
Invalid; Elan could be tired because he worked out.
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Answer:
13.5 minutes
Step-by-step explanation:
Cross multiply
3 × 576 = 128x
3 × 576 = 1,728
1,728 = 128x
1,728 ÷ 128 = x
13.5 = x
Answer:
8th: 23
11th: 32
15th: 44
22nd: 65
18th: 53
Step-by-step explanation:
The pattern is adding 3 each time:
2, 5, 8, 11, 14, 17, 20, 23, 26, 29, 32, 35, 38, 41, 44, 47, 50, 53, 56, 59, 62, 65
Hope it helps!
Answer:
0 isnt a number loll
Step-by-step explanation:
B
