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docker41 [41]
3 years ago
14

What is the theoretical probability of rolling two consecutive numberswhen rolling two dice?​

Mathematics
1 answer:
Art [367]3 years ago
4 0

Answer:

2.7%

Step-by-step explanation:

The probability of rolling the number once is \frac{1}{6}, and the probability of it happening again is \frac{1}{6}, so multiply and get \frac{1}{36}, which is approximately 2.7%

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What is ∑n=16[4(−5)n−1] equal to?<br><br> Enter your answer in the box.
Cerrena [4.2K]

Step-by-step explanation:

Geometric Sequence formula for general term:

an = a1(r^n-1)

a1 = 4 × (-5)^1-1

a1 = 4

r = -5

Summation formula for geometric sequence :

Sn = a1 ( 1 - r^n / 1 - r )

...<em>take n from the top of the summation.</em>

= 4 ( 1 -(-5)^6 / 1 -(-5)

= -10416.

4 0
2 years ago
Evaluate the expression 4 1/2 ÷ 3/4
Darya [45]

Answer: 6

Step-by-step explanation:

7 0
2 years ago
Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the co
jeka57 [31]

Answer:

<h2>A. The series CONVERGES</h2>

Step-by-step explanation:

If \sum a_n is a series, for the series to converge/diverge according to ratio test, the following conditions must be met.

\lim_{n \to \infty} |\frac{a_n_+_1}{a_n}| = \rho

If \rho < 1, the series converges absolutely

If \rho > 1, the series diverges

If \rho = 1, the test fails.

Given the series \sum\left\ {\infty} \atop {1} \right \frac{n^2}{5^n}

To test for convergence or divergence using ratio test, we will use the condition above.

a_n = \frac{n^2}{5^n} \\a_n_+_1 = \frac{(n+1)^2}{5^{n+1}}

\frac{a_n_+_1}{a_n} =  \frac{{\frac{(n+1)^2}{5^{n+1}}}}{\frac{n^2}{5^n} }\\\\ \frac{a_n_+_1}{a_n} = {{\frac{(n+1)^2}{5^{n+1}} * \frac{5^n}{n^2}\

\frac{a_n_+_1}{a_n} = {{\frac{(n^2+2n+1)}{5^n*5^1}} * \frac{5^n}{n^2}\\

aₙ₊₁/aₙ =

\lim_{n \to \infty} |\frac{ n^2+2n+1}{5n^2}| \\\\Dividing\ through\ by \ n^2\\\\\lim_{n \to \infty} |\frac{ n^2/n^2+2n/n^2+1/n^2}{5n^2/n^2}|\\\\\lim_{n \to \infty} |\frac{1+2/n+1/n^2}{5}|\\\\

note that any constant dividing infinity is equal to zero

|\frac{1+2/\infty+1/\infty^2}{5}|\\\\

\frac{1+0+0}{5}\\ = 1/5

\rho = 1/5

Since The limit of the sequence given is less than 1, hence the series converges.

5 0
3 years ago
Evaluate s(t)=∫t−[infinity]||r′(u)||du for the bernoulli spiral r(t)=⟨etcos(8t),etsin(8t)⟩. It is convenient to take −[infinity]
sveta [45]

\vec r(t)=\langle e^t\cos8t,e^t\sin8t\rangle

\|\vec r'(t)\|=\sqrt{(e^t(\cos8t-8\sin8t))^2+(e^t(\sin8t+8\cos8t))^2}=e^t\sqrt{(\cos8t-8\sin8t)^2+(\sin8t+8\cos8t)^2}

\implies\|\vec r'(t)\|=e^t\sqrt{65}

Then

s(t)=\displaystyle\sqrt{65}\int_{-\infty}^te^u\,\mathrm du=\sqrt{65}e^t

3 0
3 years ago
–9.45 + 5.4d + 9.01 = –0.1d + 0.66
bulgar [2K]

Answer:

1.838181818181818

Step-by-step explanation:

5.4d + 0.1d = 0.66 + 9.45

5.5d = 10.11

d = 10.11 / 5.5

d = 1.838181818181818

7 0
3 years ago
Read 2 more answers
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