There are 6.33 × 10²⁵ hydrogen atoms in this solution in total.
<h3>Explanation</h3>
- There are two hydrogen atoms in each water molecule.
- There are three hydrogen atoms in each ammonia molecule.
2.10 × 10²⁵ water molecules and 7.10 × 10²⁴ ammonia molecules will contain
hydrogen atoms in total.
Answer:
The answer to your question is 471.2 g
Explanation:
Data
moles of Cu(HCO₃)₂ = 2.54
mass of Cu(HCO₃)₂ = ?
Process
1.- Calculate the molar mass of Copper (II) bicarbonate
Cu(HCO₃)₂ = (1 x 63.5) + (2 x 1) + (2 x 12) + (6 x 16)
= 63.5 + 2 + 24 + 96
= 185.5 g
2.- Use proportions and cross multiplication to find the mass
185.5 g of Cu(HCO₃)₂ ------------- 1 mol
x ------------- 2.54 mol
x = (2.54 x 185.5) / 1
x = 471.2 g
Answer:
i already commented it but i want points anyways its 80 because 20x4 = 80. it said one gram equals 4 calories and there is 20 grams so basically 4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4+4
Answer:
4.D. 2KJ
5.B. close to 0 degree celsius
Explanation:
heat absorbed= heat given out
100g * 4.2 * (x-0)= 400g * 4.2* ( 20-x) where x is the new temp reached
then x= 20
i.e. the temperature of ice increases to 5 degree celsius and the temperature of water decreases to 5 degree celsius .
hope it helps
First, we need to get no.of moles of acetic acid = molarity * volume
= 0.3 m * 0.5 L
= 0.15 moles
then, we need to get no. of moles acetate = molarity *volume
= 0.2m * 0.5L
= 0.1 moles
and we have also to get moles of NaOH = molarity * volume
= 1 m* 0.02L
= 0.02 moles
according to the reaction equation and by using ICE table:
CH3COOH + OH- → CH3COO- + H2O
∴ moles acetic acid = 0.15 - 0.02 = 0.13 moles
when [acetic acid] = moles / total volume
= 0.13 moles / (0.5L + 0.02L)
= 0.25 M
and moles of acetate = 0.1 + 0.02 = 0.12 moles
∴[acetate] = moles / total volume
= 0.12 moles / 0.52L
= 0.23 M
and when we have the value of Ka so we can get the Pka from this formula:
Pka = -㏒ Ka
= -㏒ 1.8 x 10^-5
= 4.7
by using H-H equation we can get the PH:
∵PH = Pka + ㏒[acetate] /[acetic acid]
∴PH = 4.7 + ㏒(0.23 /0.25]
= 4.66