Balanced chemical equation: C(s) + O₂(g) → CO₂(g).
Oxidation half reaction: C⁰ → C⁺⁴ + 4e⁻.
Reduction half reaction: O₂⁰ + 4e⁻ → 2O⁻².
Carbon is oxidized, it changes oxidation number from zero (in carbon element) to oxidation number +4 (in carbon dioxide).
Oxygen is reduced, it changes oxidation number from zero (in molecule of oxygen) to oxidation number -2 (in carbon dioxide).
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Answer:
2H2 + O2 = 2H2O
This implies that 2 moles of oxygen is needed to react with one mole of oxygen to form 2 moles of water
It also implies that
2moles of hydrogen requires 32 grams of oxygen
?moles of hydrogen would require 8g of oxygen
2x8/32 = 0.5moles//
Explanation:
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