You have created a circuit in science class. You are using a 9 volt battery. You have generated what type of current?
2 answers:
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The empirical formula is obtained by calculating the mole ratios of the atoms in the elements.
The number of moles =mass/ R.A.M
For hydrogen, no. of moles=8/1=8
For oxygen, no. Of moles=64/16=4
The tabular solution is attached.
The number of moles =mass/ R.A.M
For hydrogen, no. of moles=8/1=8
For oxygen, no. Of moles=64/16=4
The tabular solution is attached.
Answer:
- [Ag⁺] = 1.3 × 10⁻⁵M
- s = 3.3 × 10⁻¹⁰ M
- Because the common ion effect.
Explanation:
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<u>1. Value of [Ag⁺] in a saturated solution of AgCl in distilled water.</u>
The value of [Ag⁺] in a saturated solution of AgCl in distilled water is calculated by the dissolution reaction:
- AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)
The ICE (initial, change, equilibrium) table is:
- AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)
I X 0 0
C -s +s +s
E X - s s s
Since s is very small, X - s is practically equal to X and is a constant, due to which the concentration of the solids do not appear in the Ksp equation.
Thus, the Ksp equation is:
- Ksp = [Ag⁺] [Cl⁻]
- Ksp = s × s
- Ksp = s²
By substitution:
- 1.8 × 10⁻¹⁰ = s²
- s = 1.34 × 10⁻⁵M
Rounding to two significant figures:
- [Ag⁺] = 1.3 × 10⁻⁵M ← answer
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<u>2. Molar solubility of AgCl(s) in seawater</u>
Since, the conentration of Cl⁻ in seawater is 0.54 M you must introduce this as the initial concentration in the ECE table.
The new ICE table will be:
- AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)
I X 0 0.54
C -s +s +s
E X - s s s + 0.54
The new equation for the Ksp equation will be:
- Ksp = [Ag⁺] [Cl⁻]
- Ksp = s × ( s + 0.54)
- Ksp = s² + 0.54s
By substitution:
- 1.8 × 10⁻¹⁰ = s² + 0.54s
- s² + 0.54s - 1.8 × 10⁻¹⁰ = 0
Now you must solve a quadratic equation.
Use the quadratic formula:
The positive and valid solution is s = 3.3×10⁻¹⁰ M ← answer
<u>3. Why is AgCl(s) less soluble in seawater than in distilled water.</u>
AgCl(s) is less soluble in seawater than in distilled water because there are some Cl⁻ ions is seawater which shift the equilibrium to the left.
This is known as the common ion effect.
By LeChatelier's principle, you know that an increase in the concentrations of one of the substances that participate in the equilibrium displaces the reaction to the direction that minimizes this efect.
In the case of solubility reactions, this is known as the common ion effect: when the solution contains one of the ions that is formed by the solid reactant, the reaction will proceed in less proportion, i.e. less reactant can be dissolved.
Answer:
Two
Explanation:
Lone pairs are electron pairs on an atom that resides only with one of the atoms in a molecule.
Dinitrogen pentaoxide is shown in the image attached. There are five oxygen atoms and two nitrogen atoms in the molecule. The molecule has a total of 40 valence electrons.
There are two electrons present on the central oxygen atom in the Lewis structure of dinitrogen pentaoxide as shown in the image attached.
Answer:
277.16 K is the temperature of the gas.
Explanation:
Using ideal gas equation:
PV = nRT
where,
P = Pressure of gas =
V = Volume of gas =
n = number of moles of gas =
R = Gas constant = 8.314 J/mol.K
T = Temperature of gas = ?
Putting values in above equation, we get:
T = 277.16 K
277.16 K is the temperature of the gas.