The reaction between NaOH and HCl is as follows
NaOH + HCl ---> NaCl + H₂O
for neutralisation, H⁺ ions react with an equivalent amount of OH⁻ ions.
Number of NaOH moles reacted = 0.270 M/1000 mL/L x 37 mL = 0.00999 mol
number of HCl moles reacted = 0.270 M/1000 mL x 27 mL = 0.00729 mol
HCl reacts with NaOH in 1:1 molar ratio
Number of excess NaOH moles remaining - 0.00999 - 0.00729 = 0.0027 mol
total volume of solution = 37 mL + 27 mL = 64 mL = 0.064 L
Since there's excess OH⁻ ions, we can calculate pOH value first
pOH = - log [OH⁻]
[OH⁻] = 0.0027 mol / 0.064 L = 0.042 mol/L
pOH = -log(0.042 M)
pOH = 1.37
by knowing pOH we can calculate pH using the following equation;
pH + pOH = 14
pH = 14 - 1.37
pH = 12.63
Answer:
3 Mg, 2 P, 14 O, 12 H
Explanation:
Without mincing words, let us dive straight into the solution for the problem above. This question is all about how how equations showing chemical reactions are being balanced.
From the question, we are giving the reactants: which are Mg(OH)2 and H3PO4 and in order to balance the reaction, the number of atoms in the reactants must be equal to the number of atoms in the products side of the reaction. Since, we have 3 Magnesium atoms, 2 Phosphorus atoms, 14 Oxygen atoms, and 12 Hydrogen atoms in the reactants side of the equation, the same number of atoms is expected in the products side.
Answer:
The Water Displacement method
