Answer:
what will happen to the sound is the wavelength increases thus frequency decreases so the sound decreases as he move away from her car..
Answer:
Only if the acceleration is uniform
Answer:
The final velocity of cart 1 is 3m/s
Explanation:
From principle of conservation of linear momentum, which states that sum of the momentum before collision is equal to the sum of the momentum after collision.
Momentum, P is given as mass x velocity.
ΔP = Δmv = m₁u₁ +m₂u₂ = m₁v₁ + m₂v₂
Assumptions:
- If the two carts are moving on frictionless track, then limiting frictional forces due to their weights are negligible.
- After the elastic collision, the two carts will move separately with different velocity
u₁ + u₂ = v₁ + v₂;
where;
u₁ and u₂ are the initial velocity for cart 1 and cart 2 respectively
v₁ and v₂ are the final velocity for cart 1 and cart 2 respectively
1 m/s + 5 m/s = v₁ + 3m/s
6 m/s = v₁ + 3m/s
v₁ = 6 m/s - 3m/s = 3m/s
Therefore, the final velocity of cart 1 is 3m/s
Answer:
v = 9.936 m/s
Explanation:
given,
height of cliff = 40 m
speed of sound = 343 m/s
assuming that time to reach the sound to the player = 3 s
now,
time taken to fall of ball
t = 2.857 s
distance
d = v x t
d = v x 2.875
time traveled by the sound before reaching the player
distance traveled by the wave in this time'
r = 0.143 x 343
r= 49.05 m
now,
we know.
d² + h² = r²
d² + 40² = 49.05²
d =28.387 m
v x 2.875=28.387 m
v = 9.936 m/s
