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bezimeni [28]
3 years ago
12

Anyone know how to do this ?

Physics
2 answers:
yawa3891 [41]3 years ago
4 0
No sorry I don’t know the answer try using the app Socratic
soldi70 [24.7K]3 years ago
3 0
Not really but I need points lol
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7) PE= Fwh = (72 m) (966 N) = 69552 Joules 7
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As you heat a steak on a grill, what kind of energy are you increasing in the steak?
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A 3.06kg stone is dropped from a height of 10.0m and strikes the ground with a velocity of 7.00m/s. What average force of air fr
xxTIMURxx [149]
<span>22.5 newtons. First, let's determine how much energy the stone had at the moment of impact. Kinetic energy is expressed as: E = 0.5mv^2 where E = Energy m = mass v = velocity Substituting known values and solving gives: E = 0.5 3.06 kg (7 m/s)^2 E = 1.53 kg 49 m^2/s^2 E = 74.97 kg*m^2/s^2 Now ignoring air resistance, how much energy should the rock have had? We have a 3.06 kg moving over a distance of 10.0 m under a force of 9.8 m/s^2. So 3.06 kg * 10.0 m * 9.8 m/s^2 = 299.88 kg*m^2/s^2 So without air friction, we would have had 299.88 Joules of energy, but due to air friction we only have 74.97 Joules. The loss of energy is 299.88 J - 74.97 J = 224.91 J So we can claim that 224.91 Joules of work was performed over a distance of 10 meters. So let's do the division. 224.91 J / 10 m = 224.91 kg*m^2/s^2 / 10 m = 22.491 kg*m/s^2 = 22.491 N Rounding to 3 significant figures gives an average force of 22.5 newtons.</span>
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3 years ago
If launched at the right speed, what could eventually happen to objects launched from Newton's theoretical cannon on the top of
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If the speed is higher than the orbital velocity, but not high enough to leave Earth altogether (lower than the escape velocity), it will continue revolving around Earth along an elliptical orbit. (D) for example horizontal speed of 7,300 to approximately 10,000 m/s for Earth.
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3 years ago
A driver fills an 18.9L steel gasoline can with gasoline at 15.0°C right up to the top. He forgets to replace the cap and leaves
GarryVolchara [31]

Answer:

ΔV = 0.98 L

Explanation:

First, we will calculate the increased volume using Charles' Law:

\frac{V_1}{T_1} = \frac{V_2}{T_2}

where,

V₁ =initial volume = 18.9 L

V₂ = final volume = ?

T₁ = initial temperature = 15°C + 273 = 288 k

T₂ = final temperature = 30°C + 273 = 303 k

Therefore,

\frac{18.9\ L}{288\ k} = \frac{V_2}{303\ k}

V₂ = 19.88 L

Now, we calculate the change in volume:

ΔV = V₂ - V₁ =  19.88L - 18.9 L

<u>ΔV = 0.98 L</u>

This is the volume of gasoline that will spill out.

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