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bezimeni [28]
3 years ago
12

Anyone know how to do this ?

Physics
2 answers:
yawa3891 [41]3 years ago
4 0
No sorry I don’t know the answer try using the app Socratic
soldi70 [24.7K]3 years ago
3 0
Not really but I need points lol
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When you release the mass, what do you observe about the energy?
anygoal [31]

Explanation:

Mass and energy are closely related. Due to mass–energy equivalence, any object that has mass when stationary (called rest mass) also has an equivalent amount of energy whose form is called rest energy, and any additional energy (of any form) acquired by the object above that rest energy will increase the object's total mass just as it increases its total energy. For example, after heating an object, its increase in energy could be measured as a small increase in mass, with a sensitive enough scale.

3 0
3 years ago
A uniform bar has two small balls glued to its ends. The bar is 2.00 m long and has mass 4.00 kg, while the balls each have mass
Talja [164]

Answer:

a)1.93 kg-m^2

b) 1.45  kg-m^2

c) = 0

d) 1.15 kg-m^2

Explanation:

mass of the bar M = 4 kg

length of the bar = 2 m

mass of balls m1= m2= 0.3 kg

moment of inertia of bar I= \frac{ML^2}{12}

about an axis perpendicular to the bar through its center.

a) MOI of bar + 2×m×(L/2)^2

I= \frac{ML^2}{12}+ 2m\frac{L}{2}^2

now putting the values of m, M and L as above and solving we get

I= 1.93 kg-m^2

b) perpendicular to the bar through one of the balls

I=M\frac{L^2}{3} +mL^2

I=4\frac{2^2}{3} +0.3\times4^2= 1.45  kg-m^2

c) parallel to the bar through both balls

zero as the no mass distribution along the parallel to the bar through both balls.

d) parallel to the bar and 0.500 m from it.

I=(M+2m_1)\frac{1}{2}^2

putting values and solving we get

1.15 kg-m^2

4 0
4 years ago
Jermaine and Lashonda each rub their dry hair with inflated balloons. While doing this, the other students notice that their hai
zaharov [31]

too much static electricity can cause a negative reaction such as the balloons repelling away from one another.

6 0
3 years ago
Read 2 more answers
A) State the meaning of the term principal focus as applied in lenses.​
Mariana [72]

Answer:

Explanation:

Basically, the point on the axis of a lens or mirror to which parallel rays of light converge or from which they appear to diverge after refraction or reflection.

Not sure if this is what your looking for. Hope this helps!

4 0
2 years ago
The period of a 440 Hertz sound wave is __ seconds.
snow_lady [41]
The formula relating frequency and period of a wave is simply frequency = 1 / time. Therefore, by rearranging we also see that time = 1 / frequency. The period of a 440 Hertz sound wave is 1 / 440 seconds. The speed of the wave can also be determined very simply using the formula speed = wavelength x frequency. 
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4 years ago
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