what are some challenges of scuba diving and how do pressure variations in depth affect our ability to explore the ocean?

1 answer:

5 0

Pressure variations affect our ability to explore by limiting how deep we can go. this reason is because as we go deeper in the ocean the pressure increases and can crush you if you go deep enough.

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A measurement must include both a number and a(an)

IrinaK [193]

A measurement must include both a number and an unit of measurement.

7 0

3 years ago

Find the acceleration of a hamster when it increases its velocity from rest to 8.0 m/s in 3.0 s .

Eva8 [605]

Acceleration is the change in velocity divided by time.
We can find acceleration a, by the following formula

a=v-u/t

where,
v is the final velocity (in this question v=8.0 m/s)
u is the initial velocity (since the hamster starts from rest, u=0)
t is the time taken (i,e 3.0 second)
now by applying the formula we have,

a = 8.0 - 0 / 3
= 8 / 3
= 2.65 m/s²

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Two vectors are shown. Which statement best compares the vectors?

DiKsa [7]

Answer:

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8 0

4 years ago

Read 2 more answers

The cylinder in the picture is rotating at 500 RPMs. The friction coefficients between the cylinder and block B are static=0.5 a

Tju [1.3M]

Coefficient of static friction = 0.5
Coefficient of Kinetic friction = 0.3
Angular velocity = 500 RPMs

<h3>The Radius of the System</h3>

Let R be the radius of cylinder

$m_a + m_b = 4 + 3 = 7kg$

The angular velocity is 500 RPMs

$\omega ^2 = \frac{500 * 2\pi}{60} rad/s\\N = (M_a + M_b)\omega ^2 R$

The normal force

$f = \mu N = (M_a + M_b) g\\\mu (M_a + M_b) \omega ^2 R = M_a + M_b\\R = \frac{1}{\mu \omega ^2 R}\\\mu_s = 0.5\\R = \frac{1}{0.5 * (\frac{500 * 2\pi}{60})^2 }\\R = 0.0073m\\R = 7.3mm$