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vladimir1956 [14]
3 years ago
13

Find the velocity v=ds/dt at t=3​

Physics
1 answer:
IRINA_888 [86]3 years ago
7 0

Answer:

you need at least two out of the three to get any aenser

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Airplanes moves in blank dimensions through. <br><br> What is Blank
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Blank is something empty lol
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3 years ago
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g A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0
Margarita [4]

Answer:

Explanation:

If a particle move with time and expressed according to the formula:

f(t) = 0.01t⁴ − 0.03t³

a) Velocity is the change in motion of the particle with respect to time and it is expressed as;

v(t) =\frac{d(f(t))}{dt}

v(t) = 4(0.01)t^{4-1} - 3(0.03)t^{3-1}\\v(t) = 0.04t^3 - 0.09t^2

Hence the velocity of the particle at time t is v(t) = 0.04t^3 - 0.09t^2

b) To calculate the velocity after 1 second, we will substitute t = 1 into the function v(t) in (a) as shown:

v(t) = 0.04t^3 - 0.09t^2\\v(1) = 0.04(1)^3 - 0.09(1)^2\\v(t) = 0.04 - 0.09\\v(t) = -0.05

Hence the velocity after 1second is -0.05

c) The particle is at rest when when the time is zero.

Initially, the body is not moving and the time during this time is 0. Hence the particle is at rest when t = 0second

6 0
3 years ago
4. Elements that lie along the stair step line of the periodic table are
MakcuM [25]

The answer is B. metalloids

(boron, silicon, germanium, arsenic, antimony, tellurium, astatine, and polonium)

7 0
3 years ago
A collision between two large spiral galaxies is likely to produce
Lera25 [3.4K]

A large elliptical galaxy. Hope this helped

5 0
3 years ago
The diagram below shows two bowling balls, A and B, each having a mass of 7.0 kg, placed 2.00 m apart between their centers.
AVprozaik [17]

Answer:

F = 1.63 x 10⁻⁹ N

Explanation:

Complete question is as follows:

The diagram below shows two bowling balls, A and B, each having a mass of 7.0 kg, placed 2.00 m apart between their centers. Find the magnitude of Gravitational Force?

Answer:

The gravitational force is given by Newton's Gravitational Law as follows:

F = Gm₁m₂/r²

where,

F = Gravitational Force = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = m₂ = mass of each ball = 7 kg

r = distance between balls = 2 m

Therefore,

F = (6.67 x 10⁻¹¹ N.m²/kg²)(7 kg)(7 kg)/(2 m)²

<u>F = 1.63 x 10⁻⁹ N</u>

7 0
3 years ago
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