What would the velocity of a wave traveling in a medium change?

1 answer:

8 0

Both the speed and the direction of a wave could change
at the beginning and end of the medium, when the wave
crosses from one medium into a different one.

But while the wave is moving from one place to another place
in the same medium, its speed and direction don't change.

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If the pressure of a gas sample is quadrupled and the absolute temperature is doubled. True or False

Vanyuwa [196]

The given statement"If the pressure of a gas sample is quadrupled and the absolute temperature is doubled" is false.

Answer: Option B

<u>Explanation:</u>

As we know the direct relationship between Pressure and Temperature by the Gay-Lussac’s Law,

$P_{1} T_{1}=P_{2} T_{2}$

From this, we get,

$\frac{P_{1}}{T_{2}}=\frac{P_{2}}{T_{1}}$

$T_{2}=\frac{P_{1} T_{1}}{P_{2}}$

So, according to given statement, we have $P_{2} = 4 P_{1}$

Then from the above expression, we can find out the value of $T_{2}$ when pressure increased by 4 times of initial pressure as,

$T_{2}=\frac{P_{1} T_{1}}{4 P_{1}}$

Hence, we get,

$T_{1}=4 T_{2}$

Hence, from the above expression we can say that as we increase the pressure four times, the temperature does not get doubled. So, the given statement in the question is false.

6 0

4 years ago

An air track car with a mass of 0.75 kg and a velocity of 8.5 m/s to the right collides elastically with a 0.65kg car moving to

Sunny_sXe [5.5K]

We can do this with the conservation of momentum. The fact it is elastic means no KE is lost so we don't have to worry about the loss due to sound energy etc.

Firstly, let's calculate the momentum of both objects using p=mv:

Object 1:
p = 0.75 x 8.5 = 6.375 kgm/s

Object 2 (we will make this one negative as it is travelling in the opposite direction):
p = 0.65 x -(7.2) = -4.68 kgm/s

Based on this we know that the momentum is going to be in the direction of object one, and will be 6.375-4.68=1.695 kgm/s

Substituting this into p=mv again:

1.695 = (0.75+0.65) x v
Note I assume here the objects stick together, it doesn't specify - it should!

1.695 = 1.4v
v=1.695/1.4 = 1.2 m/s to the right (to 2sf)

8 0

3 years ago

If 5J of work are done on a spring, compressing it by 12cm, what is the spring constant?

mash [69]

Answer:

k=694.44

Explanation:

PE=1/2kx^2

5=1/2k*.12^2

5=1/2k(.0144)

divide both sides by .0144

3 0