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kodGreya [7K]
3 years ago
8

What is the potential energy of a 2500 g object suspended 5 m above the earth's surface?

Physics
1 answer:
alexandr402 [8]3 years ago
7 0

Answer:

Explanation:

Potential energy, which is the energy a body assumes at a position, can be calculated using the formula:

P.E = m × g × h

Where;

m = mass (kg)

g = acceleration due to gravity (10m/s²)

h = height (m)

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Read 2 more answers
A 15 g bullet traveling horizontally at 865 m/s passes through a tank containing 13.5 kg of water and emerges with a speed of 53
blagie [28]

Answer:

0.0613°C

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the given parameters are m=15gm=15×10⁻³  V₁=865m/s  V₂=534m/s

the bullet moves with different kinetic energies before and after the penetration, therefore

Kinetic energy before - kinetic energy after = 1/2 × m × ( V₁² - V₂²)

                                                                         =\frac{1}{2} × 15×10⁻³ × (865² - 534²)

                                                                         = 3.47 × 10⁻³J

 this loss in energy is transferred to the water, therefore

change in temperature = \frac{Q}{m  C}

where c = heat capacity of water = 4.19 x 10^3

          m = mass of water = 13.5 kg

= {3.47 × 10⁻³} / {13.5 x  4.19 x 10^3 }

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