We can expect 15 times an odd number when cube is rolled 30 times .
<u>Step-by-step explanation:</u>
Moises is rolling a number cube, with sides numbered 1 through 6, 30 times. We need to find How many times should he expect to roll an odd number . Let's find out:
We know that , in a cube numbered from 1 to 6 have 3 odd number as : 1,3,5
So , probability for an odd number is :
⇒
⇒
So , Number of we should expect for an odd number when cube is rolled 30 times is :
⇒
⇒
Hence , We can expect 15 times an odd number when cube is rolled 30 times .
According to statement, it would be: 6/-8
which can be re-write as: -6/8
In short, Your Answer would be Option B
Hope this helps!
Answer:
6y^2 +3y-2+2y^2y-6y+3?
8y^2-3y+1
8y^2 - 3y+1 -this is fully simplified and cannot be simplified anymore.
Step-by-step explanation:
Answer:
5y = -2x + 31
Step-by-step explanation:
Given equation:
y =
Coordinate = (-7,9)
Unknown:
Equation of the line perpendicular = ?
Solution:
The slope - intercept format of a line is given as;
y = mx + c
where y and x are the coordinates
m is the slope
c is the y-intercept
y =
From the given equation; slope is
A line perpendicular will have a slope that is negative and the inverse of this;
slope of perpendicular line =
Since y= 9 and x = -7;
So;
9 = + C
9 = + C
C = 9 - =
Now,
y = x +
mulitply through by 5;
5y = -2x + 31