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Gelneren [198K]
4 years ago
12

in a titration 5.0 mL of a 2.0 M NaOH(aq) solution exactly neutralizes 10.0 mL of an HCI(aq) solution. What is the concentration

of the HCI(aq) solution?
Chemistry
1 answer:
Hitman42 [59]4 years ago
7 0
Volume of base(NaOH)= Vb =5 mL
Concentration of base(NaOH)= Mb =2 M
Volume of acid(HCl)= Va =10 mL
Concentration of acid(HCl)= Ma = ?
Now,
                                    Ma*Va = Mb*Vb
                                   Ma*(10) = (2)*(5)

                                   Ma= 1M
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4 years ago
The equilibrium constant has been estimated to be 0.12 at 25 °C. If you had originally placed 0.069 mol of cyclohexane in a 2.8
scZoUnD [109]

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Explanation:

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The given balanced equilibrium reaction is,

                            cyclohexane  ⇔  methylcyclopentane

Initial conc.                 0.025 M           0

At eqm. conc.       (0.025-x)M       (x) M

The expression for equilibrium constant for this reaction will be,

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Now put all the given values in this expression, we get :

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By solving the term 'x', we get :

x =  0.0027

Concentration of cyclohexane at equilibrium = (0.025-x ) M = (0.025-0.0027) M = 0.0223 M

Concentration of methylcyclopentane at equilibrium = (x ) M = (0.0027) M

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Answer:

Read Explanation

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3 years ago
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