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steposvetlana [31]
3 years ago
10

18. A swimmer steps out of a swimming pool into a light breeze. Why does

Physics
1 answer:
OverLord2011 [107]3 years ago
6 0
When the swimmer gets out, the water on her skin begins to evaporate. This process requires takes a lot of energy and that energy comes from the heat of her body. This is similar to when someone sweats. Hope this helps!
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A wrench is accidentally dropped at the top of an elevator shaft in a tall building. (a) How many meters does the wrench fall in
RUDIKE [14]

Answer:

11.25m

Explanation:

s = ut +  \frac{1}{2} a {t}^{2}  \\  = 0 \times 1.5 +  \frac{1}{2} \times 10 \times   {1.5}^{2}  \\  = 5 \times 2.25 \\  = 11.25

6 0
2 years ago
During sexual reproduction, each parent contributes
Snowcat [4.5K]

Answer:

I don't understand what exactly you're asking, but this statement is true.

Explanation:

4 0
3 years ago
What it means to say that energy is conserved as a ball fall towards ground
stiv31 [10]
Mechanical energy = Potential Energy + Kinetic Energy

if there is no friction, M.E. is conserved
as a ball falls, it is losing height. (P.E.=mgh , therefore P.E. will decrease)

the potential energy is transformed into kinetic energy which equals 1/2MV^2.

the increase in K.E. equals the decrease in P.E.

and the sum of both equals M.E.

thus mechanical energy is conserved.

hope this helps you.
5 0
3 years ago
PLEASE PLEASE HELP!!
boyakko [2]

Answer:

you have patience the distance.

Explanation:

the train leaves at 6.30.

3 0
2 years ago
A ball thrown horizontally from the top of a building hits the ground in 0.600 s. If it had been thrown with twice the speed in
ludmilkaskok [199]

Answer:

none of the answers is correct, the time  is the same  t₁ = t₂ = 0.600 s

Explanation:

This is a kinematics exercise, analyze the situation a bit. The vertical speed in both cases is the same is zero, the horizontal speed in the second case is double (vₓ₂ = 2 vₓ₁)

let's find the time to hit the ground

     y = y₀ + I go t - ½ g t²

     0 = y₀ - ½ g t²

     t = √ 2y₀ / g

with the data from the first launch

     y₀i = ½ g t²

     y₀ = ½  9.8  0.6²

     y₀ = 1,764 m

with this is the same height the time to descend in the second case is the same

    t₂ = 0.600 s

this is because the horizontal velocity change changes the offset on the x axis, but does not affect the offset on the y axis

Therefore, none of the answers is correct, the time  is the same

t₁ = t₂ = 0.600 s

5 0
2 years ago
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