1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andru [333]
2 years ago
8

Compute the voltage drop along a 26-m length of household no. 14 copper wire (used in 15-A circuits). The wire has diameter 1.62

8 mm and carries a 13-A current. The resistivity of copper is 1.68×10−8Ω⋅m. Express your answer to two significant figures and include the appropriate units
Physics
1 answer:
zepelin [54]2 years ago
8 0

Answer:

V= 2.7 [v]

Explanation:

The value of the resistance is given by:

R=L*\frac{Rho}{A}\\\\where:\\R=resistance\\L=Lenght\\Rho=Resistivity\\A=Transversal -Area

so:

R=26m*\frac{(1.68*10^{-8}ohm*m)}{\pi *(\frac{1.628*10^{-3}m}{2})^2}\\R=0.21 Ohm

We can calulate the voltage dropped using the Ohm's law:

V=I*R\\V=13A*0.21Ohm=2.7V

You might be interested in
Which of the following is the best name for CaF2?
nikdorinn [45]
Its just Calcium Flouride because as you can see it is an Ionic bond (Ca is  metal and fl is a gas usually)
6 0
2 years ago
Read 2 more answers
A rod of length 0.82 m, rotating with an angular speed, 4.2 rad/s, about axes that pass perpendicularly through one end, has a m
mariarad [96]

Answer:

Explanation:

KE = ½Iω²

ΚΕ = ½(mL²/3)ω²

ΚΕ = ½(0.63(0.82²)/3)4.2²

ΚΕ = 1.24541928

KE = 1.2 J

5 0
2 years ago
Time dilation: A missile moves with speed 6.5-10 m/s with respect to an observer on the ground. How long will it take the missil
tatyana61 [14]

Answer:

The time taken by missile's clock is 4.6\times 10^{6} s

Solution:

As per the question:

Speed of the missile, v_{m = 6.5\times 10^{3}} m/s

Now,

If 'T' be the time of the frame at rest then the dilated time as per the question is given as:

T' = T + 1

Now, using the time dilation eqn:

T' = \frac{T}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}

\frac{T'}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}

\frac{T + 1}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}

1 + \frac{1}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}

1 + \frac{1}{T} = (1 + (\frac{v_{m}}{c})^{2})^{- \frac{1}{2}}         (1)

Using binomial theorem in the above eqn:

We know that:

(1 + x)^{a} = 1 + ax

Thus eqn (1) becomes:

1 + \frac{1}{T} = 1 - \frac{- 1}{2}.\frac{v_{m}^{2}}{c^{2}}

T = \frac{2c^{2}}{v_{m}^{2}}

Now, putting appropriate values in the above eqn:

T = \frac{2(3\times 10^{8})^{2}}{(6.5\times 10^{3})^{2}}

T = 4.6\times 10^{6} s

4 0
3 years ago
How can you make the potential energy as high as possible in a magnetic field between one electromagnet and one piece of iron?
harkovskaia [24]

In step 1, to increase the potential energy, the iron will move towards the electromagnet.

In step 2, to increase the potential energy, the iron will move towards the electromagnet.

<h3>Potential energy of a system of magnetic dipole</h3>

The potential energy of a system of dipole depends on the orientation of the dipole in the magnetic field.

U = \mu B

where;

  • \mu is the dipole moment
  • B is the magnetic field

B = \frac{\mu_0 I}{2\pi r}

U = \mu\times  (\frac{\mu_0 I}{2\pi r} )

Increase in the distance (r) reduces the potential energy. Thus, we can conclude the following;

  • In step 1, to increase the potential energy, the iron will move towards the electromagnet.
  • In step 2, when the iron is rotated 180, it will still maintain the original position, to increase the potential energy, the iron will move towards the electromagnet.

Learn more about potential energy in magnetic field here: brainly.com/question/14383738

7 0
1 year ago
A spring that is compressed 14.5 cm from its equilibrium position stores 2.99 J of potential energy. Determine the spring consta
strojnjashka [21]

Answer:

284.4233 N/m

Explanation:

k = Spring constant

x = Compression of spring = 14.5 cm

U = Potential energy = 2.99 J

The potential energy of a spring is given by

U=\dfrac{1}{2}kx^2

Rearranging to get the value of k

\\\Rightarrow k=\dfrac{2U}{x^2}\\\Rightarrow k=\dfrac{2\times 2.99}{0.145^2}\\\Rightarrow k=284.4233\ N/m

The spring constant is 284.4233 N/m

7 0
3 years ago
Other questions:
  • What do u think would happen if a car had all its electrical components (such as windscreens wipers,headlights,blinkers,
    5·1 answer
  • How many chins does danisnotonfire have?
    5·2 answers
  • An astronaut's training centrifuge has a radius of 4.0m. If it goes round once every 2.5s, calculate the velocity of the end of
    9·1 answer
  • I really need help on this please help me
    5·1 answer
  • PLEASE HELP AS SOON AS POSSIBLE!!
    10·1 answer
  • What do you like about engaging to different reereational activities
    12·1 answer
  • A rock stays in the same position without moving, which law is it ?
    8·1 answer
  • Derive an equation of motion s=ut+1/2at2 for an object moving in straight line​
    14·1 answer
  • 2. Summarize how the force of gravity
    13·1 answer
  • How far apart are two conducting plates that have an electric field strength of 4. 4 kv/m between them, if their potential diffe
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!