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3 years ago

A car drives 23m/s east for 35 seconds. What is the displacement?

Physics

1 answer:

Lina20 [59]3 years ago

5 0

Answer:

805m

Explanation:

Speed = displacement/time

Speed = 23m/s

Time = 35s

Displacement = speed × time

= 23 × 35

= 805m

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The main difference between speed and velocity involves

Rashid [163]

The Correct answer to this question for Penn Foster Students is: Direction

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3 years ago

A thin film soap bubble (n=1.35) is floating in air. If the thickness of the bubble wall is 300nm, which of the following wavele

iren [92.7K]

Answer:

540 nm

Explanation:

According to the question,

The refractive index of the soap bubble, $n=1.35$ .

The thickness of the soap bubble wall is, $t=300 nm$ .

Now, for constructive interference of soap bubble.

$2nt=(m+\frac{1}{2})\lambda$ .

Now for first order m=1.

Therfore,

$\lambda =\frac{4}{3} tn$

Substitute all the variables in the above equation.

$\lambda =\frac{4}{3} (1.35)(300 nm)$ .

Therefore,

$\lambda =540 nm$ .

Therefore the visible light wavelength which is strongly reflected is 540 nm.

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3 years ago

How is velocity different from speed?

enyata [817]

Velocity, unlike speed, includes a direction.

Velocity is a vector quantity which is defined by magnitude and direction.

Speed is a scalar quantity. It is the rate at which an object moves regardless of which direction.

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3 years ago

Read 2 more answers

Which statement is an example of the law of conservation of energy

WITCHER [35]

Answer:

The law of conservation of energy can be seen in these everyday examples of energy transference: Water can produce electricity. Water falls from the sky, converting potential energy to kinetic energy. This energy is then used to rotate the turbine of a generator to produce electricity.

Explanation:

6 0

3 years ago

A 1560-kilogram truck moving with a speed of 28.0 m/s runs into the rear end of a 1070-kilogram stationary car. If the collision

Nimfa-mama [501]

Answer:

Δ KE = 249158.6 kJ

Explanation:

given data

Truck mass M = 1560 Kg

Truck initial speed, u = 28 m/s

mass of car m = 1070 Kg

initial speed of car u1 = 0 m/s

solution

first we get here final speed by using conservation of momentum that is express as

Mu = (M+m) V .......................1

put here value we get

1560 × 28 = (1560 + 1070 ) V

solve it we get

final speed V = 16.60 m/s

and

Change in kinetic energy will be here

Δ KE = $\frac{1}{2} Mu^2 - \frac{1}{2}(M+m)V^2$ .................2

put here value and we get

Δ KE = $\frac{1}{2}\times 1560\times 28^2 - \frac{1}{2}\times (1560 + 1070)\times 16.60^2$

solve it we get

Δ KE = 249158.6 kJ

6 0

3 years ago