What is the molecular formula for a monocyclic hydrocarbon with 14 carbons and 2 triple bonds?
2 answers:
The molecular formula for a monocyclic hydrocarbon with 14 carbons and 2 triple bond is C₁₄H₂₀
<h3>Molecular formula</h3>A formula that gives the number of atom of each element present in a one molecule or a compound.
<h3>Monocyclic hydrocarbons</h3>The name of the saturated hydrocarbons formed by the name attaching the perfix cyclo to the name of acyclic unstaturated hydrocarbon
The molecular formula for a monocyclic hydrocarbon with 14 carbon and 2 triple bonds is C₁₄H₂₀
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The molecular formula to monocyclic hydrocarbon is
- Monocyclic hydrocarbons that are aromatic in their lowest-lying triplet state but antiaromatic in their singlet initial state.
- The nature and quantity of each element's atoms in a molecular compound are indicated by the substance's molecular formula.
- The molecular formula is frequently the same as the formula.
- Methane's empirical formula is
, which is also its molecular formula because it only has one carbon atom.
- The hydrocarbon is known to contain two triple bonds. For each triple bond, four hydrocarbons are lost as a result.
Generally speaking, a monocyclic hydrocarbon's molecular formula is
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Answer:
Kp = 0.81666
Explanation:
Pressure of PCl₅ = 0.500 atm
Considering the ICE table for the equilibrium as:
PCl₅ (g) ⇔ PCl₃ (g) + Cl₂ (g)
t = o 0.500
t = eq -x x x
--------------------------------------------- --------------------------
Moles at eq: 0.500-x x x
Given the pressure of PCl₅ at equilibrium = 0.150 atm
Thus, 0.500 - x = 0.150
x = 0.350 atm
The expression for the equilibrium constant is:
So,
x = 0.350 atm
Thus,
<u>Thus, Kp = 0.81666</u>