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1 year ago

What is the molecular formula for a monocyclic hydrocarbon with 14 carbons and 2 triple bonds?

Chemistry

2 answers:

liq [111]1 year ago

7 0

The molecular formula for a monocyclic hydrocarbon with 14 carbons and 2 triple bond is C₁₄H₂₀

<h3>Molecular formula</h3>

A formula that gives the number of atom of each element present in a one molecule or a compound.

<h3>Monocyclic hydrocarbons</h3>

The name of the saturated hydrocarbons formed by the name attaching the perfix cyclo to the name of acyclic unstaturated hydrocarbon

The molecular formula for a monocyclic hydrocarbon with 14 carbon and 2 triple bonds is C₁₄H₂₀

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Serggg [28]1 year ago

5 0

The molecular formula to monocyclic hydrocarbon is $C_nH_{2n}CnH_{2n} = C_{14}H_{28}C_{14}H_{28}$

<h2>What is monocyclic hydrocarbon?</h2>

Monocyclic hydrocarbons that are aromatic in their lowest-lying triplet state but antiaromatic in their singlet initial state.
The nature and quantity of each element's atoms in a molecular compound are indicated by the substance's molecular formula.
The molecular formula is frequently the same as the formula.
Methane's empirical formula is $CH_4$ , which is also its molecular formula because it only has one carbon atom.
The hydrocarbon is known to contain two triple bonds. For each triple bond, four hydrocarbons are lost as a result.

Generally speaking, a monocyclic hydrocarbon's molecular formula is $C_nH_{2n}CnH_{2n} = C_{14}H_{28}C_{14}H_{28}$

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3 years ago

For each equation , write all possible mole ratios . A. 2HgO(s)>2Hg(l)+O2(g) B. 4NH3(g)+6NO(g)>5N2(g)+6H2O(l)

Dafna11 [192]

A) For balanced chemical equation: 2HgO(s) → 2Hg(l) + O₂(g).

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3) Mole ratio 3: n(Hg) : n(O₂) = 2 : 1.

B) Balanced chemical equation: 4NH₃(g) + 6NO(g) → 5N₂(g) + 6H₂O(l).

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3 years ago

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3 0

2 years ago

2C2H2 + 5O2 → 4CO2 + 2 H2O How many grams of CO2 are required to react with exactly 3.00 mol of O2? 106 g 132 g 165 g 76.8 g

cricket20 [7]

Hey there!:

Given the reaction:

2 C2H2 + 5 O2 → 4 CO2 + 2 H2O

5 moles O2 ------------- 4 moles CO2

3.00 moles O2 ---------- ( moles of CO2 ?? )

moles of CO2 = 3.00 * 4 / 5

moles of CO2 = 12 / 5

moles of CO2 = 2.4 moles

So, molar mass CO2 = 44.01 g/mol

Therefore:

1 mole CO2 -------------- 44.01 g

2.4 moles CO2 ---------- ( mass of CO2 )

mass of CO2 = 2.4 * 44.01 / 1

mass of CO2 = 106 g

Answer A

Hope that helps!

8 0

3 years ago